condutture in inventor - tilt a pipe

[mir]

Hello.
It's driving me crazy a cabbage... I've created a pipe and I can't tilt it 2 degrees... How do you advise me to do?


Thank you.
♪

 

[Tarkus]

Hello.
It's driving me crazy a cabbage... I've created a pipe and I can't tilt it 2 degrees... How do you advise me to do?


Thank you.
♪

where, in part or together, I imagine together.
Either way, you're gonna have to tilt it by 2 degrees compared to something no?
then give an angle between the axis of your tube and the axis or a face of your "something".

 

[mir]

I'm in a set of pipes... I've done what you said, but I'm afraid God will find me in a complicated case where the tubes are already bound together.

as you see in a.jpg I create the angular bond (compared to the two axes of tubes) but when I ask to realize it it speaks to me of conflict with other constraints that, however, I cannot find where they are!

I'm probably not following the right path, maybe I should change the curve...

 

[Tarkus]

from the image you do not understand 100%.
Where are you turning the pipe? Where's the pint of "Certain"?
Isn't that you have the curve and the tube that you're already fully bound?

 

[MBT]

Candalostie. . .
If the piece is "grounded" you can't move it! !

rtfm!!!!

 

[mir]

Candalostie. . .
If the piece is "grounded" you can't move it! !

rtfm!!!!

:tongue: What's that?

 

[mir]

from the image you do not understand 100%.
Where are you turning the pipe? Where's the pint of "Certain"?
Isn't that you have the curve and the tube that you're already fully bound?

I think that pipe and curve are bound because I created them with the function of tubes in inventor 11

 

[MBT]

remove the tick from "grounded" and as by magic will be free to move and you can bind it

 

[mir]

I hope that the "grounded" is not the "fixed" because I don't know how to show it.

 

[MBT]

I hope that the "grounded" is not the "fixed" because I don't know how to show it.

Sorry, I didn't read that...

I think that pipe and curve are bound because I created them with the function of tubes in inventor 11

I can't help you
are functions, like the frame generator, from which I prefer to stay away... :frown:

 

[Tarkus]

I think that pipe and curve are bound because I created them with the function of tubes in inventor 11

So you have the "professional."
I don't know him, but I guess there's a trajectory along which your piping takes place? correct me if I'm wrong

 

[stefanobruno]

are functions, like the frame generator, from which I prefer to stay away... :frown:

But then I'm not alone!!!

 

[mir]

do not need to work on trajectory ... simply insert the elements (tubo+curva+tubo) ... you can actually use the path but I thought it was easier to tilt a pipe

 

[Tarkus]

do not need to work on trajectory ... simply insert the elements (tubo+curva+tubo) ... you can actually use the path but I thought it was easier to tilt a pipe

I keep talking about things I don't know, but the curve you have to put it at 90° or can you enter a different value?

 

[Tarkus]

But then I'm not alone!!!

small ot:
instead I find it beneficial

 

[mir]

it works as for the constraints ... take an extreme of the tube and stick it to the curve

 

[Tarkus]

it works as for the constraints ... take an extreme of the tube and stick it to the curve

No, no, I was wondering if you can get the 88° curve instead of 90°

 

[Daniele_69]

if it is done with piping then you have to change the trajectory and everything automatically updates as adaptive.
Alternatively, take the individual pieces from the library and tie them as you want.

 

[Tarkus]

if it is done with piping then you have to change the trajectory and everything automatically updates as adaptive.
Alternatively, take the individual pieces from the library and tie them as you want.

It seemed to me.
But, in the case of contrajectory piping, the curve as is specified in the bom?

 

[Daniele_69]

the path is only a sketch that is then composed of the various components, therefore in separate does not appear.