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curious riddle. . .

  • Thread starter Thread starter aldus
  • Start date Start date

aldus

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My boss has fun interviewing me. . .
I ask for the help of the public. . .
...they're on a ship floating with a 8kg lead ball.
If I throw the ball into the sea the ship's floating line changes?
if you motivate the answer.. .

My answer. at risk of dismissal. . .
according to me does not change because the float depends on the volume of the liquid that moves the ship so if the ship does not change the hull the float does not change...
but in reality if on a boat I load a tide of people this sinks... so in reality
If I remove the ball the boat lightens and the floating line changes.. .
I feel a little lost. . .
I'm getting sea sickness.
 
My boss has fun interviewing me. . .
I ask for the help of the public. . .
...they're on a ship floating with a 8kg lead ball.
If I throw the ball into the sea the ship's floating line changes?
if you motivate the answer.. .

My answer. at risk of dismissal. . .
according to me does not change because the float depends on the volume of the liquid that moves the ship so if the ship does not change the hull the float does not change...
but in reality if on a boat I load a tide of people this sinks... so in reality
If I remove the ball the boat lightens and the floating line changes.. .
I feel a little lost. . .
I'm getting sea sickness.
...they are on a ship that floats with a lead ball of 8,000 kg.

Maybe that's better.
 
I did the classic high school, but...


the volume of the moved liquid (from which the thrust of Archimedes derives) depends on the shape of the hull and the portion of it which is immersed. The latter is dictated by how heavy the ship is. I would answer that the float changes.
 
...they are on a ship that floats with a lead ball of 8,000 kg.

Maybe that's better.
actually...to this answer how would you respond?

and considering that the concept is the same, changes only the size of the ball?

Consider that the question is extremely simple. . .
 
argument better:

at the moment when the ball is dropped (we imagine the one from 8000 kg of the president), the ship finds itself with a lot of thrust of float (the one that supported the 8000 kg above), so it rises and finds a position of balance with much less hull immersed (since, now, it is no longer necessary to hold on those eight tons or eight kg that are).
 
Oh, my God. .
I think it's like one of those riddles
"I throw from the skyscraper a feather of 100g and a ball of 100g: what comes first to the ground? "

Of course that changes the line of float (and of naval do not know a stern!)
the line of float is only the line of balance between volume immersed and weight of the ship in total.
the more you weigh the ship, the more you dive.
the sides could also be perfectly perpendicular to the water (a parallelepiped surrounded by half to understand), it does not float because it does not change the shape of the hull...
 
This is very easy, especially if you think of a 8000 kg lead ball.


Now I'll make you a tougher one.


glass of water in the middle of an ice cube that floats, the ice melts, the water level in the glass of how much it rises?
 
In fact, I think the line changes, but what had sent me more into crisis was the second question. .
ok motivates the answer but then asked changes how much it changes.. .
I would respond that not enough data to calculate it.. . .
and it was precisely because of this last question that I came doubt maybe the result does not change and I have the same weight... I think I have enough notions to say:
Of course it changes the floating line!
and knowing my boss will ask me what data I need.
I suddenly
at this point:
size and shape of the ship
the liquid in which it is immersed if the weight of the liquid is salted at equal volume changes.. .
...
 
ok motivates the answer but then asks if it changes how much it changes... I would respond that not enough data to calculate it.. . .
change of 8 cubic meters of hull (considering the 8000kg "transformed" in volume of water moved).... if you have a tank of 1 square meters of surface, it would rise of 8 meters...

for the ice question... while the ice does not stand on the bottom ("completely" floating), which would false the result... It is the reason why it is not exactly true what they say about the dissolution of the ice and its rise of the average level of the sea.. .
 
In fact, I think the line changes, but what had sent me more into crisis was the second question. .
ok motivates the answer but then asked changes how much it changes.. .
I would respond that not enough data to calculate it.. . .
and it was precisely because of this last question that I came doubt maybe the result does not change and I have the same weight... I think I have enough notions to say:
Of course it changes the floating line!
and knowing my boss will ask me what data I need.
I suddenly
at this point:
size and shape of the ship
the liquid in which it is immersed if the weight of the liquid is salted at equal volume changes.. .
...
But you want to know how much it changes in mm? You need hull shape and water density. Otherwise you can answer "change that as much as you just need to bring out a volume of hull that, if full of water, would weigh as the ball". and the answer would be correct without counting.
Now I'll make you a tougher one.
glass of water in the middle of an ice cube that floats, the ice melts, the water level in the glass of how much it rises?
The question is wrong. already suggests the answer...wrong!
 
Okay, I'm trying with the fulvio phrase, it seems like a good compromise.
if I consider the 8 kg of lead first mentioned sarebbbe:
0.008mcs of hull, date a 1mquadro tub rises by 0.008m which in practice are 8mm .
I don't know if I understand the formulas.. .
Thank you for the help soon I give the solution as soon as my boss arrives.. .
I hope there isn't a trap. .
 
In fact, I think the line changes, but what had sent me more into crisis was the second question. .
ok motivates the answer but then asked changes how much it changes.. .
I would respond that not enough data to calculate it.. . .
and it was precisely because of this last question that I came doubt maybe the result does not change and I have the same weight... I think I have enough notions to say:
Of course it changes the floating line!
and knowing my boss will ask me what data I need.
I suddenly
at this point:
size and shape of the ship
the liquid in which it is immersed if the weight of the liquid is salted at equal volume changes.. .
...
there would also be the volume of the "ball" that throws into the water, it would raise the level of the tub, but on the line of float would not make the difference.
 
there would also be the volume of the "ball" that throws into the water, it would raise the level of the tub, but on the line of float would not make the difference.
in fact it would only have the effect of translation of the entire system (floating line + ship) upwards than the seabed. Right?
 

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