PROG_VIT
Guest
Thank you so much mike now I'm clear.
You were very helpful.
Thanks again.
You were very helpful.
Thanks again.
PROG_VIT
Guest
Okay, these stilts don't really want to know.
Then I have the solution, like the concept and everything.
Only problem I still have are the fittings in the sketch.
I mean, when I create straight elements, it tells me that they can have living edges, and I'll tell you, of course, but so I can't solve the loft, it won't.
Could you please help me?
This is the sketch I made.
I should perform a hopper that leaves with a 50mm round and arrives at a 40x40 in a height of 30mm.
Then I have the solution, like the concept and everything.
Only problem I still have are the fittings in the sketch.
I mean, when I create straight elements, it tells me that they can have living edges, and I'll tell you, of course, but so I can't solve the loft, it won't.
Could you please help me?
This is the sketch I made.
I should perform a hopper that leaves with a 50mm round and arrives at a 40x40 in a height of 30mm.
Attachments
Pastorman75
Guest
a good procedure could be:
1) choose the number of sides of the circle (pochi=easy to do many = difficult but more precise). the number of sides must be equal to 8. we call this number x
2) make a rectangle and round the corners with a radius r. make corner fittings as building elements.
3) by leaning on the "for construction" connection to point 2, insert straight sections that interpolate the connection itself. the number n of strokes to be added for each connection is: n=(x-4)/4
example1: x=8 implies n=1
example2: x=16 implies n=3 (my example posted on the forum)
4) be careful that the traits are sufficient distance to allow the tray; depends on the thickness of the sheet but at least 5-6mm between one fold and the other there should be. possibly increase the radius referred to in point 2.
5) cut the polygon so obtained at the point you prefer so as to get an open profile necessary for the function "folding with loft"
6) create the floor at the distance you want to draw the circular exit
7) draws a regular polygon inscribed in a circumference with a number of x sides so that at least one side is parallel to the cut section (point 5) in the lower polygon.
8) cut the polygon by making sure that the cut is the same width as the lower one. even better if the lower and upper cutting points lie (the corresponding above and below) on orthogonal planes to sketches.
At this point, if everything has been done well, do "full loft" and you should have what you are looking for.
greetings
1) choose the number of sides of the circle (pochi=easy to do many = difficult but more precise). the number of sides must be equal to 8. we call this number x
2) make a rectangle and round the corners with a radius r. make corner fittings as building elements.
3) by leaning on the "for construction" connection to point 2, insert straight sections that interpolate the connection itself. the number n of strokes to be added for each connection is: n=(x-4)/4
example1: x=8 implies n=1
example2: x=16 implies n=3 (my example posted on the forum)
4) be careful that the traits are sufficient distance to allow the tray; depends on the thickness of the sheet but at least 5-6mm between one fold and the other there should be. possibly increase the radius referred to in point 2.
5) cut the polygon so obtained at the point you prefer so as to get an open profile necessary for the function "folding with loft"
6) create the floor at the distance you want to draw the circular exit
7) draws a regular polygon inscribed in a circumference with a number of x sides so that at least one side is parallel to the cut section (point 5) in the lower polygon.
8) cut the polygon by making sure that the cut is the same width as the lower one. even better if the lower and upper cutting points lie (the corresponding above and below) on orthogonal planes to sketches.
At this point, if everything has been done well, do "full loft" and you should have what you are looking for.
greetings
Mike1967
Guest
tangency is a compulsory prerogative.
follow the example attached. (for clarity I exasperated the quota "5").
the lack of need to "drawn" the edges in ears.
Attachments
Ivan1990
Guest
If not simpler, you need a diameter 200 mm, make a square with 200 sides, and fitting all angles to radius 99, open in one side a piece of line to make the profile open.
Mike1967
Guest
Yes, I did not do so otherwise he did not understand the concept. (I also drew a square reassembled. . )
in the example posted is evident the non Coradial diametricity of the circle for the loft.
I, in my models, quote the straight line, which is what makes you the difference on
Good luck with the loft.
Ivan1990
Guest
already, this speech was one of the few things that really served me in the basic course of 1 year and a half ago:biggrin:
However I rewrite that this concept is written well in the guide :finger: