stunt88
Guest
how does the thickness of a simple sheet size 1500x3000mm lean/fixed on the short sides of 1500mm so that it does not shove and falls within the limits of the arrow?
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ragnol
Guest
if you have the maximum load and arrow you want to get, the calculations like a hinge/cart beam imposing precisely that the arrow does not exceed the desired value (controling parallel also the tensions, of course. Elastic field work? ).
if the sheet is stuck at the ends according to me the easiest thing is to make a fem, or to calculate it as a hyperstatic beam. What do you know? What calculation tools do you use?
if the sheet is stuck at the ends according to me the easiest thing is to make a fem, or to calculate it as a hyperstatic beam. What do you know? What calculation tools do you use?
biz
Guest
is it better to attach a static pattern, however if I have not understood badly you can assimilate to a beam stuck at the two ends.
stunt88
Guest
ok recital come incastrata freve come procedo?
Mattymecc
Guest
There are also formulas for flat plates on the book roark's formulas for stress and strain, both for resistance and deflection calculation.
biz
Guest
If you do not have to do accurate calculations, you can consider solid as an ideal beam (principle of de saint venant).
to calculate the maximum arrow you proceed with the known formula(considering incastro-incastro and uniformly distributed load)which I hereby say below:
♪[ f=(ql^4)/(384EI) \]you get the square moment, and finally the thickness.
If you have to make more accurate calculations stick to the colleagues' advice.
to calculate the maximum arrow you proceed with the known formula(considering incastro-incastro and uniformly distributed load)which I hereby say below:
♪[ f=(ql^4)/(384EI) \]you get the square moment, and finally the thickness.
If you have to make more accurate calculations stick to the colleagues' advice.
ingegnere000
Guest
supported or framed is different for the maximum bending moment. Is she supported or framed? if it is supported, make two supports and solve like a beam idem if it is framed
meccanicamg
Guest
I think it only stacks off-format sheets on some support and doesn't want them to be folded.
ingegnere000
Guest
I think it only stacks off-format sheets on some support and doesn't want them to be folded.[/QUOTE
Va be dimensiona per 600 kg al mq ed è a posto
ragnol
Guest
If it's thin sheet stuck at the extremes, I would consider it bound by two hinges, and not stuck. In fact, the exact thickness is not able to create a constraint which, in calculation, would help not little the containment of the arrows. what would not really happen. then hyperstatic with two hinges.
this for my opinion and deeming that #stunt88 has not been cleared for two and a half months. . .
this for my opinion and deeming that #stunt88 has not been cleared for two and a half months. . .
Ghit
Guest
Excuse me is the first time I enter a forum and I know you have to look for the most pertinent discussion to your request.
I'm an engineer, but I've never made any calculations, so I only have university memories.
I ask you a humble advice: I'm trying to make a very simple alcoholic for steel shelves formed by a thin sheet folded at 90 degrees. (2 faces size 20x30cm and thickness to be defined). practically one face goes down to the wall and the other behaves as a shelf that holds the books (they would be about 10-15 magazines for shelf).
I worked with a spreadsheet in which subsequent attempts occurred the arrow, but considered this as a beam. I did the test trying to set a flat section with a base of 30 cm per h. 0.5 cm (the presumed thickness of the sheet to be sized) and time to see which thicknesses were verified.
reading the responses of the forum I read that for so small thicknesses the knot can not behave like an ink. I'll give you some advice.
I hope you don't consider this stupid request, but it seemed nice after so many years to be able to refresh by applying those concepts operationally and comparing me with colleagues!
I'm an engineer, but I've never made any calculations, so I only have university memories.
I ask you a humble advice: I'm trying to make a very simple alcoholic for steel shelves formed by a thin sheet folded at 90 degrees. (2 faces size 20x30cm and thickness to be defined). practically one face goes down to the wall and the other behaves as a shelf that holds the books (they would be about 10-15 magazines for shelf).
I worked with a spreadsheet in which subsequent attempts occurred the arrow, but considered this as a beam. I did the test trying to set a flat section with a base of 30 cm per h. 0.5 cm (the presumed thickness of the sheet to be sized) and time to see which thicknesses were verified.
reading the responses of the forum I read that for so small thicknesses the knot can not behave like an ink. I'll give you some advice.
I hope you don't consider this stupid request, but it seemed nice after so many years to be able to refresh by applying those concepts operationally and comparing me with colleagues!
MassiVonWeizen
Guest
I can tell you, as ignorant of the calculations, that:
with a scheme with the maximum size you would have made the problem clearer considering that not if on the wall is resting the face from 200mm or that from 300; moreover it is necessary to know how this sheet is made, if a simple l, if a l reinforced laterally, if an l with side and intermediate reinforcements.. .
books and magazines are two different things and both are not a unit of measurement, 10 copies of the count of montecristo are about 8 kilos (hard coverless version), 10 copies of a random magazine I imagine it is on the 5 kilos (I have no magazine to verify it); therefore needs a weight.
if you want help you should attach your calculations and results so you have a departure to discuss
in the last, the centimeters use geometries and architects
with a scheme with the maximum size you would have made the problem clearer considering that not if on the wall is resting the face from 200mm or that from 300; moreover it is necessary to know how this sheet is made, if a simple l, if a l reinforced laterally, if an l with side and intermediate reinforcements.. .
books and magazines are two different things and both are not a unit of measurement, 10 copies of the count of montecristo are about 8 kilos (hard coverless version), 10 copies of a random magazine I imagine it is on the 5 kilos (I have no magazine to verify it); therefore needs a weight.
if you want help you should attach your calculations and results so you have a departure to discuss
in the last, the centimeters use geometries and architects
Ghit
Guest
You're right, in fact, I usually deal with more architectural design. In the meantime, I thank you for being involved and preparing a scheme with the calculations I made and the object