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inventor tube

  • Thread starter Thread starter Sandra_ME30
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Sandra_ME30

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arfy 20.12.15 09:02

Good evening,
I ask more experienced users on this subject.
I have made an external diameter tube 609 thickness 3 mm. I would like to achieve the development of the sheet of this tube. but when I pass to the flat model, I get a length of 1903mm. If I do 2*pi.greco*r I should get 1913. What do you mean this thing?I don't want the model or inventor ''explains' along the average line of my tube?
Thank you.
 
Accuracy 20.12.15 19:24
originally written by arfy view message
Good evening,
I ask more experienced users on this subject.
I have made an external diameter tube 609 thickness 3 mm. I would like to achieve the development of the sheet of this tube. but when I pass to the flat model, I get a length of 1903mm. If I do 2*pi.greco*r I should get 1913. What do you mean this thing?I don't want the model or inventor ''explains' along the average line of my tube?
Thank you.
look that here is not a problem of inventor or more or less experienced users.
you don't know that the development of a pipe takes place physically in the diameter of the average thickness, it's not something that makes inventor, in fact:
609-3=606*pi greek=1903.8.
so as you see, inventor is in the right, indeed, to be precise set in this case the factor k to 0,5
 

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