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milling - painting cycle finishing

  • Thread starter Thread starter tecnico_plast
  • Start date Start date

tecnico_plast

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Good morning to all, I should make a finish on the tempered, I would like to use a strategy in the framework cycle, i.e. ap, ae and equal removal. Should the value of the removal be considered as a tooth or a spin?
 
I'm not sure I understand.
the finish on the tempered is always quite complicated especially according to the finish and the geometric tolerances to be obtained.
Honestly, I would not dare to impose ap=ae=fg (progress on the lap) also because it thinks of the same situation in which you work with:
- toric milling 4 cuts, you'd get a certain value of fz(streaming to the tooth)
- spherical cut 2 cuts, you'd get a double fz value in the same conditions as above

I recommend you to use the values provided by the tool supplier, which on hardened material must be of high quality and treated with care in terms of centering, combined with a good spindle.
for personal experience if then it comes to cut tool diameter cutters (say diameter less than 2mm) and important leakage you pay particular attention to the bendings that can come as laugh at the order of 0.0xmm
 
tolerances must be accurate, as well as finishing.
I have to finish some dowels of an injection mold, which are stagnated with males.
in some points I have to use 1.8 cutters.
I thought I was using ae=ap=fz.
 
you can do, in some cases remain very conservative considering that ap and ae are usually very reduced.
a feeling on a 50hrc finish with spherical cutter d=1,8 I would opt for
ap=0,015
Ae=0,015


reducing fz reduces progress but you should have no problem.
if you need really pushed finishes you can reduce ae and ap and even repeat 2 times the same path (to recover the bendings of the previous one)
 
we will make two finishes.
Then it depends a lot on the machine, ap=ae=0.015 on a workmanship of this type...serves a really performing stain.
 

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