MBT
Guest
What does this have to do with inventor?? ?
but beyond that...
What do you mean "how many newtons can endure the mating seal?"? ? ?
HOOPS
Guest
the seal of the fillet before it goes away....
Maybe it was better that I put in mechanics... Excuse me:
Maybe it was better that I put in mechanics... Excuse me:
radio
Guest
with those dimensions, if the material is the same for both pieces, the resistance limit (static), is given by the cylindrical part in the section at the discharge throat; the threaded part is longer than the necessary draw.
Bye.
Bye.
HOOPS
Guest
the weak point should be that, the material as said is the c40
the force I have to apply is 3000n
What you say!
Are they in lime? ?
cacciatorino
Guest
3,000 n are also holding a m16, provided the efforts are aligned. often mounts of the genus collapse because of efforts due to bending (magari generated by imperfections of manufacture).
Tarkus
Guest
quoto,and since it speaks of breaking and not of allowed loads, it would be enough (at least in traction) a section of ø much smaller than m16.
Maybe he could give us some other indication of how that joint works. .
Maybe in another section.
mir
Guest
I guess it's a flanged attack. here you find important notions on the calculation of flanges:
http://dicata.ing.unibs.it/metelli/...structure/lections foundation/bullonature.pdfIf the problem is only traction verification from the minimum section of the traction, do the traction limit calculation ... by simply imagining it as a smooth traction bar. Remember that the lengthening of the bolt involves the disassembly of the flanges...
http://dicata.ing.unibs.it/metelli/...structure/lections foundation/bullonature.pdfIf the problem is only traction verification from the minimum section of the traction, do the traction limit calculation ... by simply imagining it as a smooth traction bar. Remember that the lengthening of the bolt involves the disassembly of the flanges...
HOOPS
Guest
I would like to bring your attention to the threaded screw: m24x1.5 this and drilled on a diameter of 7, the weak point is the unloading of the thread with a thickness of 5 mm per part!!! !
on the female is the pulp that remains from the inner thread to the outer diameter 6mm per part
material is quite fragile c40 with low yielding
according to your opinion I have the possibility to change the filet from m22x1.5 or m24x1,5
I opted for the m24 thread
I want to know what you think
the axial load is 3000n
Thank you.
on the female is the pulp that remains from the inner thread to the outer diameter 6mm per part
material is quite fragile c40 with low yielding
according to your opinion I have the possibility to change the filet from m22x1.5 or m24x1,5
I opted for the m24 thread
I want to know what you think
the axial load is 3000n
Thank you.
cacciatorino
Guest
practically you have a d7 hole and the external diameter d17. remains a resistant section of 188 mmq. given the load of 3000n, you get a static sigma of 16 n/mmq, a very small value.
But you have to consider that section will be solicited even when it's not under strain because of the screw tightening preload. You have to evaluate this, according to the torque you impose.
Finally, why to file m24x1.5, do you drain from d17? Isn't that too much?
p.s.: so you can't mount the mating, you need to download the thread on the female in the filling part to get the non threaded part of the male d24.
Preparation-H
Guest
sampom
Guest
Yes,in fact for a thread m24 x 1.5 you just need a throat diameter 22.
Hi.
p-h
I wouldn't really do it. I leave all the shaft section behind the thread at ø22, smooth until the bar.
so I also excavate the problem quoted by hunter; the prehore to males to m24x1.5 is 22.8 (approximately), all the tree enters freely without downloading the hole wrapping.
@hoops in theoretical line that your section would resist a traction of about 25000 n before yielding, considering a security factor 3 for a remediated c40. if you do everything to ø22 without throat clearly even more.
greetings
Marco:smile: