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total wrong weight

  • Thread starter Thread starter jim78b
  • Start date Start date
35,57 is the value of the two-digit deficit approximation. 35.535 approximation to three digits. and it is the result of an equation, I imagine, that it does not read the real number but the fictitious number of the cell.
the correct value is what appears in the cartiglio and corresponds to the one obtained in the part.
 
as I have already told you, the value is that of the cartiglio, as it also says mass. something strange happens on the distinct, correct the distinct and see why it gives you that vaore.. .
 
as I have already told you, the value is that of the cartiglio, as it also says mass. something strange happens on the distinct, correct the distinct and see why it gives you that vaore.. .
35.53 by swx in the part .and I put in the cartilage the connection .35.57 my value obtained through my summary
 
I say to you that it has given me the same value by making the sum in the distinct and in the model, not 35.57 that I do not.
 
so I added the cells!! !
but what answer is it? How?
So, we're at the 28 post and you still can't tell how you're doing things, just give you statements that don't explain anything.
So try to be exhaustive and not as if you write sms... and also attach the design so that drake or others can see how you made the distinction.
that value that lies on the top and that brings 35.57 how the hell do you get it? automatic with equations? Do you write it by hand after you've made the notes? and the same goes for the total values of the bodies. It explains the procedure well because so far no one has yet understood it.
but I will try to be clearer:
we take the body to position 2, weighs 2.66457643 kg
if you use this approximation and multiply for 2 get 5.32915286
if I get it to 2 digits you get 2.66 that multiplied 2 makes 5.32
if you get it to a 2.7 because solidwork approximates the upper digit* that milliplicate 2 makes 5.4 (and you already have 0.08 more than before)
if you get it at 0 decimals you get 3 that multiplied 2 makes 6 with a difference of 0.68 kg
* in 2014 there is not, but in 2016 there is the possibility of rounding excess or defect, but I don't know if it also applies to weights.

you will understand that repeated for n elements of which then you make the sum the result will be different from the mass on the cartiglio that instead from the pure weight without making sums.
do it with echo if you want: you make three tables, in one you put the values that solid returns you with three decimals, in another those that returns you by putting a decimal, in another what returns you without decimals do the sums and see the differences. Of course, do not scale decimals with excel but report solid values.

I don't think I can be.
 
It's not what you wrote a few years ago that I bring back from the email:has arrived the accent that wand all!!! You were born learned!
I want to point out, because my harshness in the messages is given by banging against rubber walls to request information that should be given spontaneously.
so much to understand, that you were talking about a difference of weights between distinct cutting and cartilage it was known only to 10 posts otherwise it could be between the value of solid and that found on the balance in the workshop.
If of course it seems to you that my methods are little consonance to a forum you can report to me or ask me not to intervene in your problems anymore.
 
Good morning, I wanted to ask something inherent to the weight of a piece. I'll explain.
I have a fused piece with some tolerances even wide. is it possible to obtain the maximum and minimum weight of the piece considering the tolerances inserted in the 3d?
thank you and good Friday!
 

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