subassembled connection problem

[legnano]

Hello, everyone.
today I have a problem in inventor regarding a assembled constituted on one side and two identical subassemblies (recalled twice). the connection of the first subassembled is good but that of the second assembled is impossible; In fact, the latter repeats exactly the movements of the other but in reality, within the cinematism, the two subgroups must assume a different positioning. Therefore assembly from a series of errors.

Could you give me a few tips about it?

 

[stefanobruno]

The question is a little generic.
How did you put the two sub-axes?
have you already bound the second, what you see moving and that should not do it?
Groups or individual sub-invinculated parts move to your head and sometimes lead you to think that there is something wrong with what you have done, even if it is often not so.
if you cannot post the file, attach at least one screenshot where you see the work browser.

Hi.

 

[legnano]

Hello stefanobruno, thank you for the answer.
The second subgroup can't bind it, it gives me a mistake. cmq you understand the problem well: also recalling for the second time the subgroup (the other is already correctly bound) and leaving it free, the same moves at the moment when I move cinematism. I don't think that's a job problem.

 

[Tarkus]

Hello stefanobruno, thank you for the answer.
The second subgroup can't bind it, it gives me a mistake. cmq you understand the problem well: also recalling for the second time the subgroup (the other is already correctly bound) and leaving it free, the same moves at the moment when I move cinematism. I don't think that's a job problem.

try to check the "flexible" item for both subgroups,they should move each other independently

* = together right click in the browser on the name of a subgroup. .

 

[legnano]

Okay tarkus, now I can assemble.

Thank you all.

the wood