plate development with limited k

[dicifa]

Hello everyone, I have a problem.. .

I have to create a Greek plate that has 5 Greeks and the Greeks are made by printing. the problem is that we did a test with the mold and we found the right retreat but in inventor I can not reach the exact development because the k at some point does not give me the chance to shorten the development. inventor (if I don't remember bad) starts from 0.440, I brought it to 0.1 manon is enough for what it serves me...I also tried to increase the zeros (0.000001) but it's not yet enough. the real problem is that on these sheets there are special silhouettes and creating development manually is a mess and would take me away a lot of time... .

Can any of you help me?

allego Greek image

Thank you.

:36_1_4:

 

[Marco74]

I do not know inventor, but with solid edge you can play it with the bending radius, in the sense that besides changing the k factor you can change the fold radius, and with the combination of the two factors you can get the desired result.
I hope I've been helpful.
Bye.

 

[Tarkus]

I do not know inventor, but with solid edge you can play it with the bending radius, in the sense that besides changing the k factor you can change the fold radius, and with the combination of the two factors you can get the desired result.
I hope I've been helpful.
Bye.

I tell you, however I think inventor takes the k you give him; it's only a parameter to make calculations....,(I for sheets from 1 to 5/6 mm use 0.253 and I find myself well),

 

[dicifa]

I tell you, however I think inventor takes the k you give him; it's only a parameter to make calculations....,(I for sheets from 1 to 5/6 mm use 0.253 and I find myself well),

I am already a few years old that I have found the right k for every thickness...but since this sheet has particular retreats I can not pull out the right development. change the radius doesn't change anything. but there's no other way to adjust set the retreats?

 

[Marco74]

when they came to the company to make a demonstration of inventor I remember that in addition to the withdrawal with factor k, you could already set a withdrawal value, perhaps this is the case in which you could use since you know the withdrawal for each fold.

 

[dicifa]

when they came to the company to make a demonstration of inventor I remember that in addition to the withdrawal with factor k, you could already set a withdrawal value, perhaps this is the case in which you could use since you know the withdrawal for each fold.

Do you remember how to do it?....I think it's my call for assistance... .

 

[Stiky]

Besides the k factor, you can define a fold table, see in the help what you find and a little long to explain from scratch.

 

[cen82]

Yes, we use it. practically for each thickness, radius and fold angle, impose a value that you have to subtract to the sum of two folds. in practice for example an angle at 90° 30x30 (external measures) the value you have to put is the measure you remove to make the development of the angle. 30+30-(x)= development

 

[Marco74]

Do you remember how to do it?....I think it's my call for assistance... .

no, I don't remember it's been a few years, I remember that on the left there was a mask where to select how to apply the withdrawal, but suremante will be a custom menu.

 

[dicifa]

Yes, we use it. practically for each thickness, radius and fold angle, impose a value that you have to subtract to the sum of two folds. in practice for example an angle at 90° 30x30 (external measures) the value you have to put is the measure you remove to make the development of the angle. 30+30-(x)= development

Okay, tell me where I impose these values?

 

[dicifa]

Besides the k factor, you can define a fold table, see in the help what you find and a little long to explain from scratch.

I read after the message...now I try with the help....I didn't think about it

 

[cen82]

Okay, tell me where I impose these values?

Here. test so

 

[dicifa]

Here. test so

Hi.
I tried, but I can't... I know I'm wrong. .

allego 2 types of plates derived from a step..

the Greek roof once explained dele be 1366.5 long and instead the Greek walls must be 1422.5. .

Can you help me?

the version is inv 2011

thanks in advance

 

[cen82]

....I would do like this:
knowing the angle (155°), knowing the current development (wrong), knowing the development you want to achieve,

value to be inserted in the fold table at 155°= wrong development-development you want to get/nr folds

Try that.

 

[cen82]

....I would do like this:
knowing the angle (155°), knowing the current development (wrong), knowing the development you want to achieve,

value to be inserted in the fold table at 155°= wrong development-development you want to get/nr folds

Try that.

....corrggo, a bit of parentheses are missing....:smile:


value to be inserted in the fold table at 155°= (wrong development-development you want to get)/nr folds

 

[dicifa]

...we... I will be stunned but I can't... the result doesn't change...

 

[cen82]

Check it out.
the fold radius and the thickness you drew with. that value you must insert in the table taking into account these things, respectively:
1)thickness,
2)folding and
3) angle.

ps also controls the reference of the angle apertua that is the same from which you take the reference (see 4)

 

[dicifa]

Check it out.
the fold radius and the thickness you drew with. that value you must insert in the table taking into account these things, respectively:
1)thickness,
2)folding and
3) angle.

ps also controls the reference of the angle apertua that is the same from which you take the reference (see 4)

I'm constantly trying, but I can't get to the development I need. .
I try to ask you a courtesy: See if you can? the passages are just like you told me but it doesn't come out....:36_1_4:

 

[cen82]

I just tried. the system works but does not accept the value you should insert of 1,927 mm in table.
I'm not sure but I think that value is limited by the fold radius, maybe by changing the radius you can insert that value. however with the values you see the development is 1370. Let me know if you can.

 

[dicifa]

I just tried. the system works but does not accept the value you should insert of 1,927 mm in table.
I'm not sure but I think that value is limited by the fold radius, maybe by changing the radius you can insert that value. however with the values you see the development is 1370. Let me know if you can.

I’m going crazy!!!!...I can’t!...I’m going to attach the sheet no longer derived... try to give me a hand?

Thank you!

:36_1_1: