riccardo432532423
Guest
Do not blame him in the same ora?
PIETRO2002
Guest
Suppose you have a traction steel has a yielding load rs= 400 mpa,
to calculate the cut or twist resistance do : 400 x 0.58 = 232 mpa.
Of course, this value applies the appropriate safety coefficients.
to calculate the cut or twist resistance do : 400 x 0.58 = 232 mpa.
Of course, this value applies the appropriate safety coefficients.
riccardo432532423
Guest
one thing I found two formulas for calculating dv in the sizing of disk joints,
one is 0.2*d the other is 2.2*d+50 what is the most right one for my case?
one is 0.2*d the other is 2.2*d+50 what is the most right one for my case?
riccardo432532423
Guest
Thank you
simone1996
Guest
1/√3 see post n.7
meccanicamg
Guest
they that I had written it....0,58 is 1/√3....a divided root of three.
meccanicamg
Guest
If you've both found them, it means you can use both.
However if you use my formula it will be fine....the other is a little too much because it brings the diameter screws too external.
the screws must be half between the minimum and maximum diameter of the friction area.
♪[ Dv=\frac{(De+Di)}{2} \]
riccardo432532423
Guest
hello thanks again of attention, when you have to take the crude to make the
joint can you take it only of cylindrical form? Or even rectangular square?
Is it right when working to use the mill to make the joint?
joint can you take it only of cylindrical form? Or even rectangular square?
Is it right when working to use the mill to make the joint?
simone1996
Guest
It's a round. the crude is turned back. .
simone1996
Guest
riccardo432532423
Guest
So you can't use the cutter?
MassiVonWeizen
Guest
you can use what profile you want and any size, but if you need to get a round object it is more logical to start from a round profile with the closest possible measure to the one to get
What do you want to do with the cut?
riccardo432532423
Guest
Sorry the first question is pretty stupid. I'm pretty tired.
MassiVonWeizen
Guest
you always start from the concept that the more material I have to remove the greater the cost to get the result. cost that is given by raw material, scrap, processing time.
example:
using a 100mm hexagonal bar instead of a 30mm round to get a 25mm round means you will have to take a hexagon that weighs about 3 times as much as you will have to do the triple of passes (it's not exactly like this, but it's a simplification) and get the triple discard to throw or resell undercost.
to make that type of joint with the internal lightening is hypothesized, if the number of pieces makes it economical, to obtain it from merge with the only seat of the hole to work
example:
using a 100mm hexagonal bar instead of a 30mm round to get a 25mm round means you will have to take a hexagon that weighs about 3 times as much as you will have to do the triple of passes (it's not exactly like this, but it's a simplification) and get the triple discard to throw or resell undercost.
to make that type of joint with the internal lightening is hypothesized, if the number of pieces makes it economical, to obtain it from merge with the only seat of the hole to work
MassiVonWeizen
Guest
speculating to do it from full bar you can also do it all from fresa, obviously not manual unless you are the vest of the flyers
riccardo432532423
Guest
I wanted to do it.
riccardo432532423
Guest
these here plus the spake to make them join
MassiVonWeizen
Guest
Cosa?
I imagine you mean the areas indicated with the lines in red.
You make her come back without any problem. idem the dente di incastro tra i due semi coupling
riccardo432532423
Guest
Can't you see the picture?
riccardo432532423
Guest
but then from full circle can not do everything in fresa?speculating to do it from full bar you can also do it all from fresa, obviously not manual unless you are the vest of the flyers