3d perperdicular bitches circle

[MARCOC]

good evening to all, I have a question to ask you, in a 3d sketch, design a circle arch and then I would like on this arc to draw a circle that is perendicular to its center. I can't do it, does anyone know if w can do it in 3d sketches? ?

Thank you very much

 

[MassiVonWeizen]

a schemetto?

 

[MARCOC]

I don't know if it's very clear, but I'm trying to squash it on top.

 

[drake]

try to have the orientation of the terna that you are with...just select it with the tab key

 

[MassiVonWeizen]

try to have the orientation of the terna that is with you

but so besides not binding it is not said that it is perpendicular and passing through the center.
I found this method:
design a construction line that starts from the center of the circle and the other exthetivity is free
I make a point matching the line
drag the point until it becomes coincident to the circle
draw the free end of the line on the origin

 

[MARCOC]

Masses, I can't replicate what you did, you can't post the sketch please

 

[drake]

Of course I agree with you, you have to add other references to our case. that of the terna is sometimes convenient x because it allows you to start with the right direction and consequently move correctly in space. this is important because sometimes you draw a simple line believing it to have inserted it in a certain way instead going to rotate the sketch you see that it is in all other position

 

[MassiVonWeizen]

It's a few steps, where do you get stuck?

 

[drake]

then you could create a reference plan bound to 3d sketch in the right position and then on that go to draw the circle

 

[MassiVonWeizen]

and how do you restrict the plan that passes through the center and perpendicular to the curve?

 

[LaboratorioDieci]

make a sweep and convert the edge?

 

[MARCOC]

I don't understand how you can bind the point to the circle, it has me by mistake, but the point drags it on the arc or on the circle by 20?? ? ?

 

[MassiVonWeizen]

how do you bind the point to the circle,

drag the point until it becomes the same as the circle or the selections, select the circle and click on the coincidence.

but the point drags it on the arc or on the circle by 20??? ? ?

The image seems quite clear. Does it seem like an arch?

 

[MassiVonWeizen]

make a sweep and convert the edge?

per fare cosa?

 

[MARCOC]

I can make the construction line and bind it to the arch, but then the circle does not make it perpendicular bhoooo! !

I'll take it back tomorrow.

 

[LaboratorioDieci]

circle perpendicular to the curve with center on its end

per fare cosa?

 

[MassiVonWeizen]

never written that the line must be bound to the arch.
read the steps:
- (optional) fixed the arc so that you can better manage the other constraints without worrying that the arc moves)
-I draw a line of construction that starts from the center of the circle (which is bound to the arc) and the other esthetivity is free
. I make a point corresponding to the line (attention that is not bound as an average point)
. I draw the point until it becomes coincident to the circle or the selection together with the circle and give the coincidence
-transfer the free end of the line to the origin or center of the circle

are 4 steps

 

[MassiVonWeizen]

circle perpendicular to the curve with center on its end

Now I understand, but in this way you always have the circle at the end of the curve. if you want to have it in a different place, maybe even manageable from a quota?
for me it makes no sense to make a function only to get a sketch, if not as a last resort

 

[MassiVonWeizen]

video allego with procedure

 

[LaboratorioDieci]

Masses, forgive me, but in your procedure there is no constraint for which the circle is perpendicular to the arch. for that you need a plan