gtemp
Guest
Good morning.
a client gave me the en of the boat that is building and the breaking load of the top, asked me to dimensional a bitta.
I am a consultant to the iso 3913 and the table of figure 1 shows that I have to make a bitta dn 160.
now, always using iso 3913 I'm calculating the breaking load f using the values related to dn 160
steel 360 n/mm^2 - yeld stress 235 n/mm^2
d= 168.3 mm
from = minimum outer diameter of the tube = 166.617 mm
(d-1%)-2(t-15%)= 149.617 mm
tmax= 60% of yeld stress = 141 n/mm^2
♪ [pigreco*Tmax*(Da^2-da^2)]32 = 74417 n about 7 t
If I did not make mistakes, the result is greater than that tabled.
Now I ask myself:
1- the calculation is right?
2- if the calculation is right, is there a security factor to be multiplied to the found value?
Thank you.
a client gave me the en of the boat that is building and the breaking load of the top, asked me to dimensional a bitta.
I am a consultant to the iso 3913 and the table of figure 1 shows that I have to make a bitta dn 160.
now, always using iso 3913 I'm calculating the breaking load f using the values related to dn 160
steel 360 n/mm^2 - yeld stress 235 n/mm^2
d= 168.3 mm
from = minimum outer diameter of the tube = 166.617 mm
(d-1%)-2(t-15%)= 149.617 mm
tmax= 60% of yeld stress = 141 n/mm^2
♪ [pigreco*Tmax*(Da^2-da^2)]32 = 74417 n about 7 t
If I did not make mistakes, the result is greater than that tabled.
Now I ask myself:
1- the calculation is right?
2- if the calculation is right, is there a security factor to be multiplied to the found value?
Thank you.