calculation wall glass resistance.

[gil]

Hello everyone

I'm with this problem. I have a glass wall (all glass) fixed on the 4 sides with size 1600 (base) x 2400 (height) mm.
must resist the pressure of a crowd of people equal to 300kg on linear meter at 1 meter height. then the pressure is applied on an imaginary line.

what kind of glass and thickness should I use to ensure this resistance?
Currently, you also know the typical characteristics of the glass because that encapable of the glassmaker does not know what it sells and therefore I have to see if I remedy this value, for the most common types of glass.

Can someone help me?

 

[PierArg]

Hey, gil,
but do you have any reference rules regarding the load?
Or do you suppose that?

According to me, according to the information you reported, the glass must resist bending.
because, due to the push, it tends to sting.
from the inside side, the one from where the thrust of the crowd comes, you are "tranquillo" because the material is under compression (sided compressed fibers).
as you have guessed, the critical side is the opposite side to that of the crowd because the material is tractioned.
traction and glass do not go so well and the material begins to fracture from the outside to the inside, crumbling.

I would treat it as a flat sheet subject to bending with load distributed in the center.
but we wait for expert opinions because I am the least indicated throughout the forum on this topic.

 

[gil]

the load is indicated by the rules. This is the thrust that a parapet in crowded places must be able to resist as an accidental event.
I don't get in the details, let's take it for good.

 

[Betoniera]

the load is indicated by the rules. This is the thrust that a parapet in crowded places must be able to resist as an accidental event.
I don't get in the details, let's take it for good.

hi gil, hello to all

reference regulations on loads.
if the part is internal must resist the horizontal overloads due to the thrust of the crowd.
reference regulations d.m. 14/01/2008 technical standards on construction. Table 3.1. in particular for c3 environments (discussable of crowding) the horizontal expected load is 300 kg/m placed at a height of 1,20 m.

regulations on glass verifications.
in ntc/2008 there is nothing. you can refer to the cnr instructions (national research committee) to document n. 210/2012.
instructions cnr dt 210/2012 instructions for design, execution and control of buildings with structural elements of glass.
cnr instructions are free of charge from the cnr site.
I am not very expert in glass, but if you have any doubts, we can deepen.

Hello, next

 

[gil]

thanks to all, however not necessary normative references, at least those I have.
My problem is the calculation for the resistance for which I need a suggestion.
the most would be to be able to lay out a formula, even empirical, that I can apply.
Thank you.

 

[meccanicamg]

the system for calculation is that of flat slabs. more practically there are calculation indications qui e qui. Just do a google search and you find everything.

basically if you have a 1600 mm wide glaze and the distributed load of 300 kg/m I would say that it is enough to calculate 300*1.6 and get the load in kg to put in the middle of the plate if you use a fem, otherwise leave it as distributed load and analyze it so.

calculations for standardized cases tensions and verifications with those eligible.

 

[PierArg]

...
I would treat him like a flat plate subject to bending with load distributed in the center.
but we wait for expert opinions because I am the least indicated throughout the forum on this topic.

the system for calculation is that of flat slabs. ...

... then I took it for once!:finger::tongue:

 

[gil]

Thank you.
I'll try and see what I get out of it. the first link is a theoretical discussion, the second is a document like "I do it with the fem", but I do not have the fem. the third link leads to a document with many white pages and 1 formula, which I did not understand what it is.

I'll try to do more research anyway.

 

[studio.avarino]

not having fem or formulas available for calculating the moments in closed form can refer to the diagrams found on the technical manual of the glass of the saint gobain. on the basis of the measurements of the plate and the load indicate the thickness of the glass. because the diagrams are for the case of the uniform load you must assume a uniform load that is "equivalent" to the linear load of your case, but this is a problem of construction science. I am at the sea and I have no chance to send you a scan I hope you can find the manual on the net!