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crushing-pressed

  • Thread starter Thread starter lelepanz
  • Start date Start date

lelepanz

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excuse the title a little generic but at the moment I don't get a decent one. :
I would have a doubt... or at least I don't have the doubt, but they made me come.

I have a 2000 mm long shaft.
at one end I push with 1000 kg to the other as well.
The roller crushes.
admitting everything rigid without betrayal.
How much "short" the roller?

I hope to have explained.... :)
thanks in advance
ema
 
I don't understand.
Do you want to know how short a 2000 mm long shaft is under 10000 n in compression? What section does the tree have?

Hi.
 
No, actually, I've explained so bad.

Imagine seeing a tree in the horizontal.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
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cylinders push to the ends, but perpendicular to the axis el cylinder.
the overall roller pushes?
 
lelepanz said:
excuse the title a little generic but at the moment I don't get a decent one. :
I would have a doubt... or at least I don't have the doubt, but they made me come.

I have a 2000 mm long shaft.
at one end I push with 1000 kg to the other as well.
The roller crushes.
admitting everything rigid without betrayal.
How much "short" the roller?

I hope to have explained.... :)
thanks in advance
ema
Click to expand...
Goddamn world, it's gonna be the osque day but I don't understand how it works...
Can you make a schematic slip, even on the sliced card, and post it? ? ?
because, if I have interpreted everything well, I can tell you 2000 kg...
 
MBT said:
Goddamn world, it's gonna be the osque day but I don't understand how it works...
Can you make a schematic slip, even on the sliced card, and post it? ? ?
because, if I have interpreted everything well, I can tell you 2000 kg...
Click to expand...
eheh... I'll do a little disengagement.
But I think you played right.
 
lelepanz said:
No, actually, I've explained so bad.

Imagine seeing a tree in the horizontal.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
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cylinders push to the ends, but perpendicular to the axis el cylinder.
the overall roller pushes?
Click to expand...
Here. then it is as I had interpreted.
bhe, apply the cardinal equations of the static and solve it in 5 seconds scarce.
you have 2 cylinders that push down, each with 1000 kg.
summation of forces in y must be zero.
Therefore, if you have 2 forces of 1000 kg, on the other hand you must have a reaction of 2000 kg, like it or not.
 
"sping" 2000 kgf (20000 n approximately) in total.

if everything is rigid, the field of pressure is a line with constant distribution value.
if instead consider the deformations then the field is a surface shaped like "bone" (more pressure on the sides and less in the center)

Hi.
 
Here.
The roller is the black one.
This crushes a glass.
what force is the glass under?
because to me it is to say that the glass is always subject to 2000 kg.
then if the glass is smaller it will have a lesser suprphylae and a greater herring....

Pastorman75 said:
"sping" 2000 kgf (20000 n approximately) in total.

if everything is rigid, the field of pressure is a line with constant distribution value.
if instead consider the deformations then the field is a surface shaped like "bone" (more pressure on the sides and less in the center)

Hi.
Click to expand...
pressure or constant force?
 

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lelepanz said:
Here.
The roller is the black one.
This crushes a glass.
what force is the glass under?
because to me it is to say that the glass is always subject to 2000 kg.
then if the glass is smaller it will have a lesser suprphylae and a greater herring....
Click to expand...
then it is worth the answer that you have been given before
2000 kg and no longer talk about it....
 
Okay.
we proceed
then the resulting constant (admitting stiffness) remains a force or pressure?
of the type below the roller I can have a glass that is "largo" as the roller or narrower.
Are we talking about 2000 kg?
so the narrower glass is subjected to greater pressure?
 
Goddamn world, remains a force.... :mad:
the pressure is dependent on the area on which the force insists
if under the roller you have a 1mm2 "filo" you will have a pressure of 200,000 bar
If you have a 10 m2 sheet you will have a pressure of 0.02 bar.
 
pressure is by common practice:

force/surface

and measured in pa = [N]/[m]^

in your case, considering everything rigid, you do not have the deformation surface and the contact remains a line.
can define a measurable "linear pressure" [N]/[m] which remains constant at equal width of the slab.

if the plate has lower width, since the force is always 2000 kgf, then such "linear pressure" rises, just as you said.

Hi.
 
but sorry, for pure curiosity mixed with sadomasochism
Was there anyone who supported the opposite?? ? ?
 
MBT said:
but sorry, for pure curiosity mixed with sadomasochism
Was there anyone who supported the opposite?? ? ?
Click to expand...
yes... my boss....
I also made him a design.

You're on a table. at the other end we put another one.
I'm off the table.
How much does it crush me?
What if I just put my hand on it?
:
 
Um...
examples with people under the tables are always furnaces of ambiguous interpretations. . :eek::rolleyes:
 

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