custom type line creation

[Salvo Donzello]

Hello I am trying to create a custom linetype that meets my design needs, the line I need to realize I think is not very complex but I couldn't set it up. I would be able to realize a line that has a horizontal extension of 4.5 units of measurement, with an empty space of o.25 and therefore another line of size 1.7 but this autlima vertically and that has a snap from the intersection point in the axis y of 0.15 and then continue with a new space of 0.25 units. I'd be very grateful. Thank you.

 

[Cristallo]

You can't make a three-dimensional guy. It's a line, so for definition two-dimensional

 

[sircame]

Of course you can do, now I don't remember the procedure well, but on google you find it without problems, there are various tutorials.
I created a binary style line type for when I have to draw more detailed planes than normal.

but if you wait maybe someone can explain the procedure better but I think there are some guides in this forum too.

 

[Cristallo]

you can only do it by inserting a shape into the definition of typeline. Then it becomes a problem if you have to move it to someone. if you do not send the shape will result the lack and the tlinea will not be displayed correctly.

 

[smemo]

using the expresstools mkltype command is easy enough to create custom lines.
in your case, as it rightly points out crystal you have to use shapes (shape).
autocad uses by default a file of "ltypeshp.shx" forms for which using the contained forms:
track1, zig, box, circ1, bat and amzigzag we can already do something without having to worry about
upload them before using our custom line type.

for your example, just copy the code to a text file that I called "donzello.lin"

*donzello,donzello
a,4.5,-.25,[TRACK1,ltypeshp,y=1,s=.85],-.25

 

[Salvo Donzello]

thank you so much you have been of great help, I imagine that if I want to reverse the position of the perpendicular down I must vary y with -1

 

[smemo]

Yes, with y=-1 reverses the insertion point of the shape and then you get the perperdicular down.
the same result however you get it also without changing type line, but inverting the direction of the vertices of the line.

 

[Salvo Donzello]

:finger: thanks again