Determine cylinder force

[torok]

Can you give me a hand? I need to dimensional a pneumatic cylinder to open a lid as an attached pattern. The lid is hinged in its fc weight is about 17 kg. I'd like to open it with a b hinged pneumatic cylinder and connected to the c door.
I'm losing my arms.
I was proceeding with fcilindro= fc 17xbraccio 671 / arm cylinder 102. But I'm not sure about arms at all.
thanks to all for the collaboration.

 

[Kaji]

I apologize for the answer that is probably wrong, but I think that the arm of a force is simply the distance of the action line of the force itself from the center of rotation of the hinge, so the fc force that is vertical has as arm 574 while the force of the cylinder is tilted of 16° and its arm should be found with the geometry of the triangles.

 

[Focus]

I apologize for the answer that is probably wrong, but I think that the arm of a force is simply the distance of the action line of the force itself from the center of rotation of the hinge, so the fc force that is vertical has as arm 574 while the force of the cylinder is tilted of 16° and its arm should be found with the geometry of the triangles.

the "cylinder arm" in the starting condition is the perpendicular distance to the bc segment, from the segment itself to the fulcro a.

Hi.

 

[torok]

thanks guys always useful a comparison with you.