dimensional an orbital motor

[max81]

Bye to all,
I would like to learn how to dimension an orbital motor, and looking on the manual of oleodynamics of speich and peels is reported a diagram of the isorendiments, but it is not explained much on their use, therefore I ask lumi to someone.
from the comer catalog, I extracted this diagram of the motor glt315 (prese by case) with 326,3 cm3/turn of displacement:




correct me if I'm wrong, assuming I want a pair of 400 nm and 150 rpm, from the embroidery diagram that needs a pressure diff of about dp=90 bar and a flow rate q=50 l/min, also my work point in the diagram is found in the ellipse with yield 88%.

how do I use this performance, in particular is volumetric or hydrochloric performance?

hypothesized that it's the dromechanic performance I would have: mt = (dp * vg * uhm) / 62,8 where dp = pressure diff. (90 bar), vg = displaced (326,3 cm3/giro), uhm hydrochloric yield (0,88) and mt the torque provided by the engine, then replacing we get a minimum torque mt = 411.5 nm.
Is my speech correct?

Thank you.

 

[Messerschmitt]

the indicated torque values are already those that you have out of the tree, while the pressures and the flow rates are those that you have to give in. in other words there is no account to do, because the diagram already takes account of the hydraulic and volumetric performance.
the areas where the engine works well.

 

[max81]

Hello messerschmitt,
thanks to the answer, correct me if I'm wrong, so if I want 400 nm and 150 rpm, from the embroidery diagram that I need a flow of about 50 l/min and 85-90 bar of pressure diff., also from the point on the diagram I know that my engine is working "good", that is in the area with greater efficiency (88%).

Thank you.

 

[Messerschmitt]

Yeah, that's what you say. as verification you can do:
power to the tree = 400 nm * 150 rpm = 6283 w
hydraulic power input = 50 l/min * 87 bar = 7250 w
yield = 6283 w / 7250 w = 0,87
In other words, in view of the error introduced by the reading from the diagram, an output of 88 % is obtained.

 

[max81]

Hello messerschmitt,
Thank you for your explanation.