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disposition loads analysis fem forklift

  • Thread starter Thread starter Taipan95
  • Start date Start date

Taipan95

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Good morning.
I am trying, for exercise, to design a forklift on wheels. the instrument serves to facilitate the emptying of a barrel full of liquid, lifting it and tilting it in favor of gravity.
I have synthesized the cinematism that, through linear actuators, should allow me to get the two positions of work.
At this point I would like to carry out a fem analysis to dimension the components of the chassis of the cart as well as the arms of the cinematism, and I would like an opinion on the modeling of the loads to be inserted in the analysis.

the final job position is the one where the barrel has the maximum "balance" and therefore should be the most critical one. in this position, the force acting is definitely the weight of the load that is lifted and held tilted. I have a doubt about the force of the actuator, instead: in the final position, the actuator exercises a force that keeps the arms lifted, but in a fem analysis I have to take into account? I first doubted whether to consider the actual force on the lifting arm (f1 in the image) or the reaction to the base of the actuator (f2). After some reflections I thought that the actuator would be modeled as an infinitely rigid auction (because I don't care about his contribution in the fem, because I just want to study the frame) without adding any other force outside the weight: the hydraulic force of the actuator, in fact, is the daughter of the dynamic balance and depends on the external load (in this case the weight of the barrel) so if the tract as an shaft the load of the barrel, through the rod, in fact, will be transmitted to all the frame and I will not have to add anything else.

nb: obviously on the frame I will go to account of welds, bolts, various pins that are part of the assembly.

Could I have your feedback? Thank you.

links of workplaces (to understand the operation): jobs-hosted at imgbblink of the scheme of forces: schema-forze hosted at imgbb
 
all the forces exchanged between the various members are placed, otherwise the weight contrasts what?
the cylinder pushes and reacts, so either insert an infinitely rigid bar that in a fem is a bit deranged and instead replace it with two forces.
much depends on the simulator you have available.
 
Maybe I figured out why you say it doesn't make sense to put the bar: If I used a rigid rod, I would be transferring the weight of the barrel directly to the base area of the frame where the piston is hinged... but in reality the thrust reaction of the piston is different from the weight of the raised barrel, because the arms of the forces (barile weight and piston thrust) are different and from the balance of moment I get by force two different values. . .

as an alternative would the double force be applied where I indicated f1 and f2? would it be two equal and contrary forces?
 
Maybe I figured out why you say it doesn't make sense to put the bar: If I used a rigid rod, I would be transferring the weight of the barrel directly to the base area of the frame where the piston is hinged... but in reality the thrust reaction of the piston is different from the weight of the raised barrel, because the arms of the forces (barile weight and piston thrust) are different and from the balance of moment I get by force two different values. . .

as an alternative would the double force be applied where I indicated f1 and f2? would it be two equal and contrary forces?
exact
 

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