enter a parametric formula

[Spit19]

Bye to all,
I am new nx user and I am using it for the exercise for my course of engineering studies.
How do I insert a formula that decreases me when I grow one?
I explain better: I have a solid initially cylindrical then ends conical and the exterminity is round practically to increase
the height of the solid has to decrease! ! !
Thanks to who will help me! ! ! ! !

 

[ceschi1959]

Bye to all,
I am new nx user and I am using it for the exercise for my course of engineering studies.
How do I insert a formula that decreases me when I grow one?
I explain better: I have a solid initially cylindrical then ends conical and the exterminity is round practically to increase
the height of the solid has to decrease! ! !
Thanks to who will help me! ! ! ! !

I'd say that I didn't understand much, if maybe you put a sketch with two odds and the variation of the diameters I can take a look at. What version of nx do you use?
Hi.

 

[Spit19]

I'd say that I didn't understand much, if maybe you put a sketch with two odds and the variation of the diameters I can take a look at. What version of nx do you use?
Hi.

Hi I use version 6.
then I explain even better my screw has a diameter of 4.8 mm initial (the cylindrical part) and a height of 13 mm total the final diameter is 3.3mm
now the diameter must vary according to the height. example if the screw has a height of 14.5 mm the diameter must be 3 mm or if the screw is 11.5 mm
the diameter of 3.6mm.
to vary the height of 1.5 mm (more or less) the diameter in turn will have to either increase or decrease of 0.3 mm....
I hope I've been clear. . .
another thing how do I remove those surfaces that have not been eliminated? ? ?

Thank you very much.

 

[ceschi1959]

no, you were not clear even if the intent I see it in the attached pdf. I'll explain why you haven't been clear: do not define the law of variation of the diameter. In fact, if it were a linear law and departed from the initial diameter 4.8, after 13 mm you should have a diameter of 2.2. in fact 13/1.5=8.6 (periodic) which represents the number of variations of 0.3 mm on the diameter. Am I right?
Bye.
p.s. must the thread be constant? What command did you do?
ri p.s. I saw the commands in pdf

 

[Spit19]

then the screw must have these characteristics:
height 13 mm
initial ø 4.8 mm (initial cylindrical part)
after 6 mm the screw assumes a conical profile with anng. 6°
ø final 3.3 mm.
now I have to relate the varying height (always of 1.5 mm) with the final ø (always of 0.3 mm) increasing or decreasing.
still attached my life.

You have some advice to give me so I can make it five days I'm working on it. I'm freaking out. . .
Thank you very much

Hi.

 

[ceschi1959]

Hi and I'm sorry I'm late but I prefer to do more on Sunday...

I still don't get a few things back and maybe that's why you're not going out. it is not possible to make a cone with a inclination of 6th and at the same time to respect the conditions that at the increase of 1.5 mm the radius decreases of 0.15 mm because the tangent of 0.15/1.5 does not 6°.

attached a file in which I set a formula (alfa=arctan(0.15/15)) used for drafting an extrusion. Take a look.

Another aspect that does not convince me is the way you swept by leaning on a projected curve of a propeller.

Hi.

 

[Spit19]

Hi and I'm sorry I'm late but I prefer to do more on Sunday...

I still don't get a few things back and maybe that's why you're not going out. it is not possible to make a cone with a inclination of 6th and at the same time to respect the conditions that at the increase of 1.5 mm the radius decreases of 0.15 mm because the tangent of 0.15/1.5 does not 6°.

attached a file in which I set a formula (alfa=arctan(0.15/15)) used for drafting an extrusion. Take a look.

Another aspect that does not convince me is the way you swept by leaning on a projected curve of a propeller.

Hi.

Okay perfect! ! !
However you have wrong interpretation to vary the height of 1.5 mm must vary the final ø of 0.3 as I wrote in the previous post!!! !
another thing like you would sweep it!!!!

Thanks again!!! !

 

[Spit19]

Okay perfect! ! !
However you have wrong interpretation to vary the height of 1.5 mm must vary the final ø of 0.3 as I wrote in the previous post!!! !
another thing like you would sweep it!!!!

Thanks again!!! !

no excuse I was wrong to read you spoke of radius!! ! !
I don't know what to say because this is written in the specifications:
you realize the first part I consider it cylindrical
" provides a first section of 6 mm in height with a conicity of 2°, useful to stabilize the plant in the most cortical area of the receiving bone, and a conicity apex 6° but with variable length, in order to better adapt to the morphology of the bone crests, thanks to the progressive reduction of the apical diameter.
the conical profile thread has a step of 0.6 mm and a depth of 0.4 mm, to provide more contact surface there where you meet a more spontaneous bone.
the outer edge with a progressive profile, with an angle of 60° is complete until the apex of the plant.
the crown microfilettatura, has the same shape of the actual spire, but with half-step.

 

[ceschi1959]

Try to take a look at this.

Hi.

 

[ceschi1959]

Dear Spit19, I expected a positive and negative feedback.

greetings

 

[Spit19]

Hello excuse me you are right!!! Thank you for the help I definitely go ahead with the first example about the formula!!! thank you so much!! ! !