gear project

[atofras]

hi, I want to design a gear for a pack holder and not know where to start, what can I take as an example to make a scheme?

 

[gerod]

Maybe if you make us understand the application! ! ! !
so you don't understand!

 

[atofras]

an ingrain with on one side a motor and on the other a track or a screw for fat to climb or move my basket

 

[c._mauro]

That's too vague.
I would say first of all to understand what toothed wheel you need: straight teeth? conical? etc.
then serves the reduction report, which is fundamental (I place it with letter u)?
This would also serve data (angular velocity for example, service coefficients), unless you want to plant a randomly dented wheel.

Forgive me for some inaccuracies, but I have no manuals or notes with me.

 

[sampom]

then serves the reduction report, which is fundamental (I place it with letter u)?

usually the transmission ratios are indicated with the i tiny. .
so everyone should understand.

greetings
Marco:smile:

 

[c._mauro]

usually the transmission ratios are indicated with the i tiny. .
so everyone should understand.

greetings
Marco:smile:

my mistake, gear ratio u and instead reduction ratio i, perdonatemi.

 

[gerod]

Well, I would say that in order to calculate a gear you need a lot, first of all what you have to do (lift, move, etc.)
If you make a scheme, we can help you. but you need some extra details!
Are you talking about basket? Who knows? loads or people?
then we talk about rack not of track!
give us some extra data, so I see oo^1 solutions!

 

[meccanicamg]

always the same problem atofras... You must be clear, post a scheme, give information. otherwise if you just say you have to design a gear, well I tell you that you have to check/size according to one 8862:1987 as indicated in other my posts.

 

[cesius79]

on boys we don't do the squirt!:biggrin: "i" is the ratio of reduction "t" (Greek letter) that of transmission...one is the reciprocal of the other.
if you don't say the basket if you bring the shopping or profiled by 2 tons we can design as well duckopoli.. . .
you need weights, and a general scheme of what you want to do.

 

[Jeffcott]

Hello everyone, I am currently having to design something similar to atofrà maybe I can take advantage of you, :biggrin: in the good sense of course! I have to lift a load of 50 kg (full weight, excluding the engine) for a height of 3 m and to raise everything I thought to use a rack instead of a belt drive. do you help me in the sizing of components and in the choice of engine?

 

[PierArg]

Hi.

If you place a box of what you have in mind, we can help you. van well also four lines written on a handkerchief

Hi.

 

[sampom]

Hello everyone, I am currently having to design something similar to atofrà maybe I can take advantage of you, :biggrin: in the good sense of course! I have to lift a load of 50 kg (full weight, excluding the engine) for a height of 3 m and to raise everything I thought to use a rack instead of a belt drive. do you help me in the sizing of components and in the choice of engine?

Jeff.. that you repeated? :biggrin:
Anyway, you already know:You must have post schema and "values in the field".. or what are we talking about?

greetings
Marco:smile:

 

[Jeffcott]

Here's a draft, but I'm pressing that it's just a scheme to give an idea!
I am still considering the use of a belt transmission for the same application.
any clarification also for a belt transmission is well accepted. See you soon! :smile:

 

[Jeffcott]

Forgive me sampom: the load to be lifted has a mass of 30 kg, the maximum height is 3 m, the speed of ascent is 0.2 m/s. I wait for your help on the right solution and how it proceeds in the choice of engine, belt or rotation etc.

 

[PierArg]

I meant a scheme with 2 indicative quotas. but is the engine solution that carries with all the load obliged?

 

[Jeffcott]

No, the engine solution is not obliged! for this I am thinking of the belt solution, in this case I place the fixed motor at the bottom (or at the top) and the belt allows the movement of a sleigh appropriately positioned.

 

[PierArg]

I would definitely be for the wild boar.

at this point you remain the diameter of the pulley and there are all the data to proceed with a preliminary sizing

 

[Jeffcott]

Okay, go for the belt drive.
the pulley will have diameter 90 mm.
the sled I make it move on steel swallows:
μrs (static) = 0.778
μrd (dynamic) = 0,42

 

[PierArg]

then, you have to move your 30 kg load with a speed of 0.2 m/s, so:

motor power = 30* 9.81*0.2 = 60 miserable watts
pulley rotation speed = v/r = 4.44 rad/sec
where v=0.2 m/s
r= radius pulleys in meters = 0.045

the speed in turns/minute of the pulley will be v*60/(2*pgreco) = 42.46 rpm

assuming that the engine turns to 1450 you will have your nice reduction ratio:

i= 1450/42.46 = 34

now you open horizons for all other necessities side considerations:

- take into account the performance of the electric motor (0.95 approximately)
- take into account the performance of the reducer
- take into account the fact that the couple you have to provide must also win the inertia of the pulley, and since it will be big enough, it is not to be neglected.

I hope I gave you a good start...

Hi.

 

[Jeffcott]

thank you pierarg, but this dimensioning I had already made. What I don't remember at all is exactly what you're talking about.
in which equations are taken into account the performance of the engine and the gearbox?
How do I know that the couple must also win the pulley inertia?
Finally, I do not remember what criterion is chosen between dentate and trapezoidal.