help explanation on torque motion and force kg

[Danlau]

Bye to all,
I would like to calculate that torque movement needed to mix a mass of 50 kg and to raise a mass of 150 kg.

not being of the sector, I have documented myself to great lines on the internet, and I seem to have understood that to trace back to the necessary nms of the torque movement, I should start from the kg strength.

I should do:
50 kg (my mass to mix) that should be the same thing as kg strength.
multiply by 9,80665 ( 1 kgf = 9,80665 nm)

50 x 9,80665 = 490,3325 nm of torque movement necessary for
mix my mass of 50 kg.

and the same calculation should repeat it for the mass of 150 kg to be lifted.

Is this right? If not, could you explain to me how to go back to the torque movement? Of course I do not demand perfect values, but also with a tolerance up to 5%.

thank you so much for the help guys!!!! and apologize for my ignorance in the matter :frown:

 

[meccanicamg]

Hello, danlau,
first I would like to clarify some concept:
- it's called torque moment and not torque motion
- is defined as "moment" the product between force and arm as long as they are orthogonal between them (so if they are not necessary to disassemble and calculate the actual arm or the actual force)
- the torque moment is a moment that acts around its main axis causing a twist (such as pasta ... fusilli)
- in the international system the moment is expressed in n*m (in newton * meter)
- in the practical system the moment is expressed in kg*m also called kilogrammeter
- x kg = x [kg] * 9.81 [m/s^2] = y [N]in your specific case I cannot tell you that the calculation is or is not correct, as:
- for the first example of a mass to be mixed it is necessary to consider the density, the shape of the blades that mix, geometric factors and consistency of the material to be mixed
- for the second example of a mass to be raised, it is necessary to see how to lift, calculate the actual arms and forces that can change instantly depending on the lifting scheme.

see some of the concepts, if you have any plans, we don't come to the end

 

[Fulvio Romano]

what mechanicalmg says is correct, unless a formal error that makes the skin happen to us "purists" :biggrin:
the "torque motion" is an internal feature of a material loaded with a "pair". so you want to calculate a couple and not a twisting moment. but this is only philosophy.

I still imagine you remember this discussion:http://www.cad3d.it/forum1/showthread.php?t=21246and maybe you can find some interesting point in this other:http://www.cad3d.it/forum1/showthread.php?t=21622p.s.
post a scheme, we can help you moooolto better

 

[meccanicamg]

the "torque motion" is an internal feature of a material loaded with a "pair"

I fully agree even if I did not want to further split the louse in 4, cmq it is true that a pair is calculated, while the torque moment is an internal action of the material due to the application of a couple... but this is a detail:biggrin:

 

[Danlau]

thanks mechanicalmg and fulvio for the intervention.

In the first case, I have to mix mozzarella pasta. I don't know how to describe the texture of the dough, I can tell you that it has a 50% moisture. the consistency may seem that of fresh pasta, but a little harder.
the system for mixing is composed of 2 parallel and horizontal screws (diam and step of about 200 mm), which push the mass on the bottom of the tank. from the base and sides of the screws, there is about 1 cm of space on the walls of the tub. at the end of the screws, where the dough is conveyed, there are about 6 cm of space from the tub, and at the top of the screws, there are about 20 cm of space from the wall of the tub.
This is because when the mass is pushed to the bottom, it finds space upwards, and when it collides on the upper wall, it is pushed back (but always in the space above the coclees) by the mass that follows it. This until it falls back into the coclees. so you create a horizontal vortex that kneades.

As for lifting, I would like to replace an oleodynamic piston with a gear motor, but you should let me know what I should explain to you to help you understand better.

Thank you very much x help! ! ! ! !

 

[sampom]

But you should let me know what I should explain to you to help you understand better.

placed patterns with the values at stake for both issues.
to understand "in words" is not simple, you need to see "disegnini":biggrin:.

greetings
Marco:smile:

 

[gerod]

other than split the louse in 4!!! this is the catarsis of mechanics or physics (depending on the points of view).
However, in the catalogues of manufacturers of gearboxes we talk about torque (almost always expressed with the symbol m or t).
Give us a pattern!
Hi.

 

[Danlau]

thanks to all for the interventions, these days as soon as I prepare a sketch.
hello and thanks again

 

[reggio]

hi, the calculation of the torque or torque moment, is, as they told you, a simple calculation, a multiplication of the force by the arm, the difficult, presumably, will calculate the force of "meaning", if you think about it, the 50kg or those that are of the material to mix, really say little... Think of 50kg of balls and 50kg of concrete, they will probably require a different effort while being always 50kg, if then the cement dry...
despite the professionalism and preparation of the boys who have already answered you, I think you will need a far greater approximation of 5% that you asked at the beginning...

are cmq curious to read the proseguo.

soon and good work! :