[inventor 2010] problem with design cam

[User1]

Now I see what I can do. Give me a few days. However, he has nothing special!

 

[Ilario]

animated the angular bond ^_^
p.s. you must also put them in contact group

you are a great!!! I didn't think about it! in fact it is perfectly free!

Now I see what I can do. Give me a few days. However, he has nothing special!

we know how to use it, only that the utility in terms of use is really equal to 0.01%. I think stefano meant they could do it better.

 

[stefanobruno]

In fact, it's a perfect match!

...only that utility in terms of use is really equal to 0.01%....

I would use it intensively, in the plants we make we must check the areas occupied by the load in the curves of the path.
even with the contact group I never managed to get a useful result.
we take refuge in corner doing it with autocad step by step (which boto !! ) )

Ciao.

 

[User1]

I'm working on it, tomorrow I'll try the stage where you're having trouble, but what's that throat for? I would like to insert the image but how do I do it? for the moment if you want to see the work I am doing go to my site: designerstacatia3d.blogspot.com

 

[Peppe]

I would use it intensively, in the plants we make we must check the areas occupied by the load in the curves of the path.
even with the contact group I never managed to get a useful result.
we take refuge in corner doing it with autocad step by step (which boto !! ) )

Ciao.

remains a complex animation, because inventor must calculate the path as the component follows it. so if you have complex assemblies, maybe aactivity and pc not very performant you can not do much. the aid in question is simple but if you have more connected parts iventor you c..a on! !

 

[User1]

Hello, I solved your problem! you in the drawing represented the view on a plane of the cam, with the respective angles that correspond to the axial translations of the particular regarding an orthogonal axis to the "superior and lower" surfaces, the detail will perform an axial translation at the moment when a "x" point of the circumference of the cylinder reaches a certain number of degrees. well I calculated the length of the arches on a floor with the formula: rad=2x3.14x angle in degrees/360grades, once obtained the result of radiants I calculated the length of the arc: arc= r x rad, generating the development of the cam on a plane. with the emboss command I gave depth to the surface. the game is done! if you want to see the result you can see it on my blog: http//progettistacatia3d.blogspot.com
Hello! ! !

 

[User1]

I tried to do this!