cliff23
Guest
Bye to all,
I have a lever pulling a mechanism with an opening of 21st. to the same lever
A bowden cable is attached that leads me to release another mechanism
with an opening of 29°.
The problem is that the first lever has an arm of 47mm, thus carrying out a circle arc of 51.28mm while the second lever (2' mechanism) has an arm of 68.77mm with a described arc of 34.81mm.
My problem is how to multiply the shift of the first lever to release the 2' mechanism. You can suggest something.
I have a lever pulling a mechanism with an opening of 21st. to the same lever
A bowden cable is attached that leads me to release another mechanism
with an opening of 29°.
The problem is that the first lever has an arm of 47mm, thus carrying out a circle arc of 51.28mm while the second lever (2' mechanism) has an arm of 68.77mm with a described arc of 34.81mm.
My problem is how to multiply the shift of the first lever to release the 2' mechanism. You can suggest something.