parallel bond: what logic? who is on the negative x?

[graziano-g]

Hi.

the title leaves little to the imagination or maybe not...

ergo: either I am stunned or ....

design two lines, a vertical and to its right a horizontal and eliminate the constraints that in automatic inventor puts, the lines are therefore free to move and to be oriented at will, however I leave them as I drew it.

In this way if you assume as origin x=0 any point that stands between the two lines and I apply the parallel bond between the two lines that changes orientation independently from the selection order will always be that of the two that stands on the right side of the other, then in this case the horizontal one.

if they are staggered on y then depends on which side they are one compared to the other in reference to the average point of the horizontal one.

At least this is the conclusion I came to.

Is that true?

Is there any way to change that or to make it assumed as a baseline/reference the first of the two that is selected independently from the side/position in which it is located?

in case you want to apply this bond to a line or part of a geometry in relation to another not completely bound this causes changes in shapes....

What do you think?

Hello, thank you.

 

[Ilario]

blind:
put the bond of "fixing" to what you want to hold as "base" and then apply the bond of parallelism. then remove the "lucchetto" from the first.

 

[graziano-g]

Bye.

thanks ilario, certainly the acrocchio works, however I expected a logic type autocad, the first selected condition the second.

patience fits.

Hello and thank you.