problem con serie fori su ipart

[stefra]

Good evening, everyone!
I have the following problem with the attached file : I have to create a series of panels with a base which increases by 170 mm per panel; on these I have to create a series of holes (with a step less than 500 mm) which increases when the length increases.
I have created an ipart with table in which I tried to set parameters that change the set of holes , but when step from measure 308x1158 to 308x1328 I close the inventor and crashes...
any advice is accepted!

 

[pompeo79]

I tried and crashed, too.
I don't see any heroes, it might be or the broken file, or something that doesn't act well (sometimes stupid like parametric structuring)
I had something similar to the processing level and I re-proposed it with your measurements.
I don't know if that was what you were looking for.

 

[stefra]

by Pompeo79, first of all thanks for the attention;
I tried your file and it works perfectly!
I probably screwed up with too many sketches and parameters.
Your solution is much simpler and more linear. :finger:
I do not understand why on the expression of n_fori add +1.5 on at the end.

thanks again and hello

 

[pompeo79]

by Pompeo79, first of all thanks for the attention;
I tried your file and it works perfectly!
I probably screwed up with too many sketches and parameters.
Your solution is much simpler and more linear. :finger:
I do not understand why on the expression of n_fori add +1.5 on at the end.

thanks again and hello

Hi stefra,

should be 1 theoretically (minimum length/length) + 1 , being two holes outside the measurement.



1.5 basically as a correction factor

for example in case with base 818

the holes should be 3, but if instead of 1.5 I had put 1 I would 2.27 (which inventor rounds to 2)

with 1.5 I 2.77 inventor round to 3,

the same for the other holes, since the increase is constant, 170 mm, always satisfying the condition distance holes <500

 

[stefra]

I understand, thank you for the clarification!

 

[Peppe]

Hi stefra,

should be 1 theoretically (minimum length/length) + 1 , being two holes outside the measurement.



1.5 basically as a correction factor

for example in case with base 818

the holes should be 3, but if instead of 1.5 I had put 1 I would 2.27 (which inventor rounds to 2)u

with 1.5 I 2.77 inventor round 3

the same for the other holes, since the increase is constant, 170 mm, always satisfying the condition distance holes <500

to overcome the decimal problem there are parameters to be inserted in the formulas that allow you to round for excess or defect. Look at you. This is what debate

 

[pompeo79]

to overcome the decimal problem there are parameters to be inserted in the formulas that allow you to round for excess or defect. Look at you. This is what debate

:finger: thx