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the usual propeller

  • Thread starter Thread starter mrgreen2011
  • Start date Start date

mrgreen2011

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Bye to all,

I know it's a topic that has been treated here hundreds of times, but I can't find with the search for a thread under catia.
I should make a pin with a hollowed-out stretch. the propeller part should ideally be the result of a milling cut that removes material from a pin moving along precisely a path to propeller (the axis of the milling is therefore always normal to the axis of the pin). Could you give me some tips? I'm using a v5-r19

Thank you so much!
 

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  • Perno.webp
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Hi.
it is to draw the profile of the excavation (for example a triangle or a circle, depending on the excavation to be done) on a meridian plane and then to draw the propeller (you find it in the wireframe & surface design) with appropriate axle and pitch.

It's not difficult.

of the noble
 
Hi.

I did some tests, but I still have some doubts (be patient).
I attach an old drawing that represents exactly what I should do. on straight strokes, I think the cut is done with a rectangular section, but also on the part of the propeller returns to you? (I know that in sw they had made an ad hoc function that basically cut using not a profile but a solid).

Thank you so much!
 

Attachments

I found this "solution" (attached), according to you is correct?
in some forums I found suggest using a "swept volume", does anyone know anything about it?

Thank you very much
 

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Hello, everyone.
I think the work you have attached is not good for at least two reasons. 1) from what you understand from the drawing that you have previously placed the milled part presents a helical tract (what is the passage of the helix?) of 18 mm between two straight strokes respective of 10 mm and 14 mm. 2) if the milled part must be realized with a tool of the type a candle then the milling should be flat and orthogonal to the axis of the milled piece. After all this pippone I have to say that I have also made an attempt but I have found great difficulties to realize the path of the tool, precisely because it is not only a propeller, but of something more complex. I'll make more attempts at curiosity, if I ever let you know. I hope you have solved the problem in the meantime. I wish everyone a good evening.
 
Hello stefano 1950,

Thanks for the answer. No, I'm still, I haven't found a solution yet.
the passage of the propeller is found considering that in the 18 mm of helical tract the angle of rotation is 90 degrees.
 
Okay mrgreen2011!
I'll take into account the fact that you gave me. to resent us.
 

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