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toothed wheel processing

  • Thread starter Thread starter alberto85pc
  • Start date Start date

alberto85pc

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Bye to all,
I should work on a z16 m2.5 toothed wheel to accommodate a bearing.
how can I assess the maximum diameter of the processing?
the bearings I'm evaluating are:
di12 dest 28
10 dest 24.
the diameter of the foot is 33,75mm and both bearings seem to me relocated (especially the one with 28mm dest)

thanks to all
 
It is always preferable to attach a design to have a common language and to help with visual references.
I don't understand your question.
tail do you mean with maximum diameter of processing?
What do you mean by foot diameter in reference to bearings?
What are you asking, a numerical value to perform at the lathe?
tail has to do with the gears with the processing of the fella diameter seat of the bearing

or your question is vague and missing of essential information or is poorly formulated to give a precise answer
 
I should accommodate a bearing within a dirrified teeth wheel (z=16 m=2.5).
being the space relocated, I wanted to understand how to determine the maximum outer diameter of the bearing. currentmete I put a bearing 6001-2rs1, but of meat on the radius regarding the diameter of foot I have 3mm poor
example for calettators is the formula for checking the diameter, is there something similar?
the wheel is hardened.
Thank you.
 

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therefore your request does not concern processing, but the choice of bearing. in this case the title is misleading and would be the case of changing it by asking for help from moderators.
As for your question if you are a mechanical expert you should know very well that the data you provided is absolutely insufficient to give you an answer.
search in the forum calculation bearings or with similar terms that surely is already spoken, without considering that the site of the skf, to say the most known, puts to provisions free of charge and without registration tables and formulas for the choice of bearings
 
Thank you, but the bearing I chose, the problem is the seat. as you can see from the image there is very little meat. the various bearing builders provide shoulder diameters. In my case, I would like to see if 3mm on the toothed wheel radius are enough or not.
 
Thank you, but the bearing I chose, the problem is the seat. as you can see from the image there is very little meat. the various bearing builders provide shoulder diameters. In my case, I would like to see if 3mm on the toothed wheel radius are enough or not.
you wrote:
I wanted to understand how to determine the maximum outer diameter of the bearing.
However, apart from this, it is certainly little, but if it resists depends on the application. In your case, however, I would avoid the plague by adding a further fragility such as the seeger headquarters which removes further material.
 
Why not use a roller bearing if you don't have axial thrust? has lower radial dimensions.
 
your case is similar to that of satellites in the epicloidal gearboxes for which I would keep the space under tooth not less than 2 times the module; Obviously it also depends on how the gear is solicited, for example if the transmissible torque is used all and if there are bumps during operation.
if you have durability problems for a smaller bearing, it is worth the suggestion given by @ pietro2002.
seen from the image the space is definitely insufficient.
 
how is the bearing inserted? Is there any interference? How much? After you have answered this question you can give you an answer, empirically though if you use the formula of the calettators I would be quiet.... and remove the two seegers by replacing them with glue. as you have already suggested massive

Hi.
 
the title and first post are well different from the request posted later.
a gear will be dug inside to accommodate a bearing.
the gear will have a loss of carrying capacity if you exceed a certain diameter.
the debate is identical to This is what already done.
then with the chart you have to try to stay within k=1.
 
basically you can drill up to 20mm in diameter without losing in capacity, then k=1.
with diameter 24mm we have k=1,521.
with diameter 28mm we have k=2,366.

therefore means that in bending if a gear in 42crmo4 reclaimed with 4nm/mm surface tempering, you will get that digging will bring 4/k.cb306b2bca16965eb3859913a249e91d.webp
 
Last edited:
Bye to all,
I should work on a z16 m2.5 toothed wheel to accommodate a bearing.
how can I assess the maximum diameter of the processing?
the bearings I'm evaluating are:
di12 dest 28
10 dest 24.
the diameter of the foot is 33,75mm and both bearings seem to me relocated (especially the one with 28mm dest)

thanks to all
in this question, how much confusion, how many requests, how many proposals, how many unnecessary questions! Tree has asked a simple question, providing all the necessary data.
teeth16 x module 2.5 = 40mm. primitive diameter.
primitive diameter + twice module 2.5 = 40+( 2 x 2.5 ) = 45 mm. external diameter.
primitive diameter - ( 2 x 7/6 x m ) = 40 - (2 x 7/6 x 2.5 ) = 40 - 5,83 =34,2 mm. inner diameter.
now, an internal turning of 28 mm diameter, within a diameter of 34,2,
gives a circular ring of 3mm thick which, as they all agree, is poor.
the diameter 24 mm. gives a distance from the teething bottom (34.2 - 24 ) : 2 = 5 mm. double module size, therefore more than enough.
the bottom diameter of the elastic ring of 25,2 mm x1,30, does not weaken the toothed wheel.
the ball bearing could be a 12 24 6 or 15 24 5, number two if there are, or rightly rollers, to have support width and greater inner diameter.
important not to mention: I think that the shaft is fixed and that the toothed wheel turns, why the outer ring of the bearing should be mounted stuck in the hole of the toothed wheel, as it is on this ring that the load turns.
If there was even a slight game, a sealant would be useless.
 

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