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transmission motorcycle

  • Thread starter Thread starter namu1769
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Come on, I don't believe you don't have a book where you're talking about sizing trees solicited torsion. . .
We don't understand each other, I mean the millerighe, those scanned trees, but they have a lot more teeth.
 
We don't understand each other, I mean the millerighe, those scanned trees, but they have a lot more teeth.
those are born to convey the couple that can transmit the tree... Find the diameter of hazelnut you need and then choose the groove that has the diameter of just higher hazelnut.
 
those are born to convey the couple that can transmit the tree... Find the diameter of hazelnut you need and then choose the groove that has the diameter of just higher hazelnut.
Clearly, I mean the unified millerighe, because if I do not err should have type 14/15 teeth, but from normal tables there is no more than 6/8 teeth
 
then returning to the main point, knowing that 390 nm and broken, (83 * 1.943 * 2.462, neglecting for now the relationship chain pinion and crown) as dimension the millerighe grooved shaft that comes out? because as I said in my manual they don't talk about it and I have no idea how this type of tree fits.
Let's talk.
If the tree had a tongue, it would oppose the bike and therefore you have a specific pressure on the side of the tab and a cutting force.
If I had a channel din 14 would be n tabs that they hold.
with the millerighe, which is nothing but a straight teeth gear with pressure angle of 30° or higher, does the same work on its side.

Quantitatively we can go to look at the nienann what it proposes as a calculation.Screenshot_20210518_204746.webpScreenshot_20210518_204849.webpso depending on the type, striated or grooved you still have the calculation model. according to regulations you can have a standard profile table.
 
those are born to convey the couple that can transmit the tree... Find the diameter of hazelnut you need and then choose the groove that has the diameter of just higher hazelnut.
as first approximation you can also calculate so, but then are the teeth that hold and not only the hazelnut that should not twist.
 
Let's talk.
If the tree had a tongue, it would oppose the bike and therefore you have a specific pressure on the side of the tab and a cutting force.
If I had a channel din 14 would be n tabs that they hold.
with the millerighe, which is nothing but a straight teeth gear with pressure angle of 30° or higher, does the same work on its side.

Quantitatively we can go to look at the nienann what it proposes as a calculation.View attachment 62201View attachment 62202so depending on the type, striated or grooved you still have the calculation model. according to regulations you can have a standard profile table.
Okay, thank you very much for the material, now I throw down two calculations.
 
as first approximation you can also calculate so, but then are the teeth that hold and not only the hazelnut that should not twist.
from tests performed on the field, applied growing torque up to breaking and have always twisted or broken the trees. Your teeth never!
 
from tests performed on the field, applied growing torque up to breaking and have always twisted or broken the trees. Your teeth never!
who does not tempt the trees can be that they wax the teeth, perhaps with tolerances lascge hub/shaft and maybe tilted. Unfortunately, we see mechanical processes of fear on machinery.
certainly on the bikes the quality is higher and I agree that rather it draws the tree.
 
who does not tempt the trees can be that they wax the teeth, perhaps with tolerances lascge hub/shaft and maybe tilted. Unfortunately, we see mechanical processes of fear on machinery.
certainly on the bikes the quality is higher and I agree that rather it draws the tree.
I forgot to say that the band must be as long as the diameter of the tree, though, something less is still possible. I think the calculation should be done to find the minimum band.
 
OK there are, I made two basic calculations and from this tab that I forwarded to you I took that with dp 28.50 with 34 teeth. using as mt 397 nm comes a diameter of hazelnut from 25.41, making the verification is acceptable.
 

Attachments

  • millerighe.webp
    millerighe.webp
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OK there are, I made two basic calculations and from this tab that I forwarded to you I took that with dp 28.50 with 34 teeth. using as mt 397 nm comes a diameter of hazelnut from 25.41, making the verification is acceptable.
is the length? there is to do the calculation of the specific pressure on the teeth, but you will see that it will be enough on the 25 mm...
 
is the length? there is to do the calculation of the specific pressure on the teeth, but you will see that it will be enough on the 25 mm...
for specific length and pressure on teeth I don't know how I could do
 
for specific length and pressure on teeth I don't know how I could do
there are the formulas that I posted of nienann, which in fact is the only way to calculate the ability of a channel. You look at them.

post 24
 
I forgot to say that I considered a c45 steel with 800 n/mm2 of rm
Tempered? ricotto? cleared? What?
Keep in mind that no one will ever make a chocolate tree... because there is bending, twisting, bumps and fatigue. I can't see a c45 tree on a motorcycle. and 800mpa breaking load on a 30/40mm essay should be tempered.

see attached card.
 

Attachments

OK there are, I made two basic calculations and from this tab that I forwarded to you I took that with dp 28.50 with 34 teeth. using as mt 397 nm comes a diameter of hazelnut from 25.41, making the verification is acceptable.
Something's wrong.

we take full shaft diameter even only 25mm.
area= 3,14•d2/4=490mm2
Mt.
tau torsione = 16*mt/3,14•d3=130mpa
rm=800mpa
tau adm =0,58•rm/3=154mpa

thinking about fatigue, impacts, bending and cutting, because there is attached the pinion I would say that it is a little thin and however the material is not suitable. it is necessary to pass to a steel to be reclaimed at least bound as a 39crnimo3 and to tempt the teeth...and to base a good bonifica a heart.
Screenshot_20210518_225756.webpBut the channel could be okay.
 
I'm sorry if I'm intruding, it's about "admissible pressure," but how is it? is used in various calculations but I never found a unique formulation, sometimes I read in this forum rs/1.5 and others to take it from books and tables. How should we proceed?
 
I'm sorry if I'm intruding, it's about "admissible pressure," but how is it? is used in various calculations but I never found a unique formulation, sometimes I read in this forum rs/1.5 and others to take it from books and tables. How should we proceed?
on the ancient books of good practice is considered as admissible pressure 100mpa for steel up to rm 700 and then 200mpa for rm 1200-1500mpa.
then often you do rm/6 and you use that. Surely you should not get to yield otherwise you fingerprint everything.
 

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