development of u -calandrati profiles

[KRLE]

Hello
after various searches around I thought I would ask this question to you hoping to find someone who has some experience regarding
displacement of profiles to u. ( 25x12sp4 - 30x15sp4.5 -35x17sp5.5 – 40x20sp6).

having more and more often need to respect diameters imposed by the application, I found myself several times not to adjust exact profile development using solidworks.
precise that solidworks I use since 98 and so far I have solved all the problems but this time
I couldn't find a valid "k factor" to bend the profiles while for the diameters up to 2000mm I can stand it (doctor k 0.43), the most serious thing and that increasing of error diameter between sw and carpenter becomes + big and then I am forced to trust him, or make the displacement and then make adjustments to the work cutting or adding of the profile.

I know for certain that these applications are very used in the agricultural sector (dryers – silos ..). and surely the system to calculate developments of the profiles there.
or I would like to know if there are any software that does it perfectly.
I'll attach you some photos to make you know what I'm talking about.

I appreciate your advice
Thank you very much.

 

[re_solidworks]

Hello
after various searches around I thought I would ask this question to you hoping to find someone who has some experience regarding
displacement of profiles to u. ( 25x12sp4 - 30x15sp4.5 -35x17sp5.5 – 40x20sp6).

having more and more often need to respect diameters imposed by the application, I found myself several times not to adjust exact profile development using solidworks.
precise that solidworks I use since 98 and so far I have solved all the problems but this time
I couldn't find a valid "k factor" to bend the profiles while for the diameters up to 2000mm I can stand it (doctor k 0.43), the most serious thing and that increasing of error diameter between sw and carpenter becomes + big and then I am forced to trust him, or make the displacement and then make adjustments to the work cutting or adding of the profile.

I know for certain that these applications are very used in the agricultural sector (dryers – silos ..). and surely the system to calculate developments of the profiles there.
or I would like to know if there are any software that does it perfectly.
I'll attach you some photos to make you know what I'm talking about.

I appreciate your advice
Thank you very much.

did you try to make the K factor coincide with the section center?

 

[KRLE]

thanks for the answer

sincerely not
Now I'll try to make some examples

 

[geppetto]

I'm sorry. I'm the one who, after 10 years of sw, ran into me or lost something? Does sw not develop the profile in the image or does it?
Maybe you only develop the cylindrical face apart?
I feel like I'm getting off the clouds. .

 

[KRLE]

No.

You haven't reluctantly swed yet
you have to use other tools like these .
look at tree

 

[geppetto]

I don't open the file, I have 2010. from the tree I understood you make good trips to get a result that seems to be still approximate. Um...
I can't help you. :redface:

 

[SolidUser]

I wanted to inform you that sw2012 allows linear development of forms of that kind.

 

[pometto]

can't you just multiply between the outer diameter and 3.14? I think it's the easiest way.. cmq you have to consider that the sheet is not always the same, by experience you have to add to the svliluppo calculated the thickness of the sheet used. For example if the development is 1000mm and the sheet is 1.5mm the final result is 1001.5, you will see that in 99% of cases it is almost perfect! listen to the expert

 

[Mike1967]

I wanted to inform you that sw2012 allows linear development of forms of that kind.

it will be as you say but I immediately noticed, doing tests, that the fk is influential so I doubt
on the goodness of development.

 

[SolidUser]

it will be as you say but I immediately noticed, doing tests, that the fk is influential so I doubt
on the goodness of development.

I'll ask you a few questions:
1) have you read that I have written linear development?
2) Do you know why I put it in bold?
3) would you have preferred that sw continue not to develop such forms or this new possibility would you be comfortable?
4) do you know that to correctly calculate the development of these objects you need specialized software that cost as much as a sw license?
5) do you think that the development as it is could be comfortable or with some correction solution, would you bypass the limit of this inaccuracy?

 

[Oldwarper]

I'll ask you a few questions:
1) have you read that I have written linear development?
2) Do you know why I put it in bold?
3) would you have preferred that sw continue not to develop such forms or this new possibility would you be comfortable?
4) do you know that to correctly calculate the development of these objects you need specialized software that cost as much as a sw license?
5) do you think that the development as it is could be comfortable or with some correction solution, would you bypass the limit of this inaccuracy?

I'll make you one.
what difference is between the above and this phrase:

1) this is a linear development.
2) I have highlighted it because it is linear and does not consider the bending factors
3) is an aid to the development of such forms, it does not give an exact measure (and here it would be better that the help specified it, I did not subhand it, maybe so, n.d.m.)
4) gives an approximate measure, but since it is not a specialized sw you can settle
5) if you need more precision you need specialized software (and also for those a test it always takes, n.d.m.)

It's all right, but we're adults and vaccinated.
If a command gives an approximate solution, it's necessary to know, because whoever doesn't know it and trusts it, then he can start loving surprises.

One can guess, looking at the parameters he asks and the result, but if he asks and doesn't respect them, at least a non-bypassable warning (not enough the help) would take us. even if it's a "beta" function.

 

[sampom]

what difference is between the above and this phrase:

...forsake the empatia?
:smile:

 

[Mike1967]

oldwarper answered your questions, soliduser.
to me if they could save this news news (Note...) in bold) improving management
of multibody plates.

 

[KRLE]

thank you for the answers and your comers but as I could see you have gone away from the main question .

I would like to ask the precise question for this matter.

how much should be profile development at u 40x20x6 to get diameter exterior (application as the first photo a sx) of 2742 mm?

I read that there would be software for these applications.
If someone has any experience about it, I would like to know what software it is.

 

[maxopus]

thank you for the answers and your comers but as I could see you have gone away from the main question .

I would like to ask the precise question for this matter.

how much should be profile development at u 40x20x6 to get diameter exterior (application as the first photo a sx) of 2742 mm?

I read that there would be software for these applications.
If someone has any experience about it, I would like to know what software it is.

I wouldn't think twice: 2.742x3,14159.
at the limit you get longer than 3-4 cm, a flex shot and operating systems.

 

[KRLE]

perhaps at the beginning I did not specify one thing – importantand
after calandrato (curved) this profile to make it a ring , it should be inserted into a cylinder where and very difficult to go to cut
so you have to be precise from the beginning

 

[pometto]

by making the account strictly by hand I who are capable of it without relying on 3d programs development considering the so-called factor "turn" the development of the profile 40x20x6 is 58x2742. I entrusted myself to the simple mathematician otherwise once how did they do it? cmq on sti cases here do not rely on 3d programs or other people, try to get there alone!
Of course I've been exhaustive trying to calculate your development and compare it to the result I gave you...
cmq calculation is simple = 40+20+20-6-6-6-6+factor fold (2)=58
2742x3.14+factor fold=8584
allore the bending factor is nothing but a value to add to the theoretical result, I used my bending factor by calculating it after various tests...
cmq see you... Try so it should be fine.
Hi.

 

[maxopus]

by making the account strictly by hand I who are capable of it without relying on 3d programs development considering the so-called factor "turn" the development of the profile 40x20x6 is 58x2742. I entrusted myself to the simple mathematician otherwise once how did they do it? cmq on sti cases here do not rely on 3d programs or other people, try to get there alone!
Of course I've been exhaustive trying to calculate your development and compare it to the result I gave you...
cmq calculation is simple = 40+20+20-6-6-6-6+factor fold (2)=58
2742x3.14+factor fold=8584
allore the bending factor is nothing but a value to add to the theoretical result, I used my bending factor by calculating it after various tests...
cmq see you... Try so it should be fine.
Hi.

This is a hot profile, what does the bending factor have to do?

 

[Mike1967]

This is a hot profile, what does the bending factor have to do?

I believe it refers to the development of the u 40x20. (the profile at u considers it sheet).

 

[maxopus]

I believe it refers to the development of the u 40x20. (the profile at u considers it sheet).

I don't comment.