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bolted flange in pressurized conduct

  • Thread starter Thread starter alequatt
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alequatt

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Hello, everyone. I have two half-sections of conduct connected by a bolted flange. inside the conduct flows fluid under pressure. I wanted to ask you if it is correct not to consider the axial tensions of mariots since there is no melt that closes the conduct. I also wanted to ask if the internal pressure (without considering the weight of conduct and fluid weight) has some effect on the bolting project. to be clear, if you have to size bolting only taking into account pressure, what formula should I use? thanks
 
Hello, everyone. I have two half-sections of conduct connected by a bolted flange. inside the conduct flows fluid under pressure. I wanted to ask you if it is correct not to consider the axial tensions of mariots since there is no melt that closes the conduct. I also wanted to ask if the internal pressure (without considering the weight of conduct and fluid weight) has some effect on the bolting project. to be clear, if you have to size bolting only taking into account pressure, what formula should I use? thanks
I'd say if you're a technician, you have to put a pattern at least in pencil on a sheet.
What are the semi sections? Will it be two tubes? two pipes?
if you combine two tubes with a flange for each tube is like the single pressure tube.Screenshot_20200322_230319.webpthe forces on a stretch of tube, continuous or discontinuous are those that are in a shirt of a cylinder:
img_20190504_204010-jpg.53403
So if you take this trunk and cut it and put the welded flanges on it you still have an axial tension
so if you have 100bar, this pressure is discharged on the tube section by generating an equivalent traction force on the screwdriver.
 
Hello, thank you for the answer. the section of conduct is a tube, it is formed by the two semi-sections (always tubes) connected to each other by the flange. my doubt was precisely on the axial sigma since in the section of conduct there is no melt on which the pressure is discharged. Thanks again!
 

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