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impossible ball?

  • Thread starter Thread starter catapulta00
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catapulta00

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hello to all I'm going crazy, I can't create a ball like football with 20 hexagons and 12 pots, someone can give me some advice
 
You could create a set formed by parties to form from hexagons and pentagons, the greater difficulty would be the constraints, perhaps the pin bond would solve the problem.
 
I remember that he talked about it some time ago, the procedure was also explained.

try to do a search on the forum.
 
hello to all I'm going crazy, I can't create a ball like football with 20 hexagons and 12 pots, someone can give me some advice
this discussion already exists link
http://www.cad3d.it/forum1/showthread.php?t=7038then I attach you image of the ball that I made in catia v5 composed of 20 hexagons and 12 pentagons. .

I drew the two figures separately and then assembled them in 6 steps.

1 sketch of geometry (hexagon)
2 ball building
3 projects the sketch on the sphere
4 cuts the ball with projected geometry
5 thickness 2 mm of the cut surface (hexagon)
6 assembles among them first hexagons and then pentagons

greetings

 

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il football ball is a solid that does not belong to the family of platonic solids that are, on the other hand, regular polyhedra which respect the following rules:
- faces are regular polygons
- all faces are equal and overlapping
- solid corners are equal to each other

Such solids were associated with platoon to the constituent elements of the universe:
tetrahedron (fire) , cube (land) , octaedron (air), icosahedron (water), dodecahedron (quinto essence)
the old soccer ball was therefore made up of unequal faces (pentagons and hexagons) .
the images you see are variants, called "vacui".

The baseball baseball baseball (like tennis) instead it consists of two equal parts that "beam".
 

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I did it with the wf4.
I saw that the maximum circumference must be 68-70 cm.
I only had to calculate the sides of the hexagons/pentagons and developed the model. came as beautiful and precise as that of the image posted by zimmy.
I have to post it?
But I was thinking of relating the size of the polygons to the circumference of the ball so as to allow an easy modification of the model.
 
hello to all you are too good at this forum. However I was successful and the procedure is similar, perhaps the same as rs4; I first built the truncated ichosaedro and then wrapped by a sphere, I projected the edges of the polyhedron on the surface and fortunately the ball came out.

I have only two problems:
1) the sides of polygons are not all the same, but I think we can solve it with a polyhedron report
2)I don't understand why when I run the whole 20 mm size model fails me; I solved this by saving an iges file and then I worked on that model, but I don't understand why I can't make a 20mm scale projection.

hello and thanks again
 

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I know this but I think it can be solved by cutting the idiosaedron well, but explain why it does not project me when the model is small (20mm)
 
hello to all you are too good at this forum. However I was successful and the procedure is similar, perhaps the same as rs4; I first built the truncated ichosaedro and then wrapped by a sphere, I projected the edges of the polyhedron on the surface and fortunately the ball came out.

I have only two problems:
1) the sides of polygons are not all the same, but I think we can solve it with a polyhedron report
2)I don't understand why when I run the whole 20 mm size model fails me; I solved this by saving an iges file and then I worked on that model, but I don't understand why I can't make a 20mm scale projection.

hello and thanks again
I did differently from you...
I designed the figures, hexagon and pentagon singles in 2 different parts and then I assembled them in one product

I will train you step of operations
 

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continues the sequence

it would be interesting to see the various ways performed by colleagues exposing their processing steps

greetings

 

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continues the sequence

it would be interesting to see the various ways performed by colleagues exposing their processing steps

greetings

I also used the same method.
How did you calculate the exact measurement of polygons?
 
I also used the same method.
How did you calculate the exact measurement of polygons?
this is the bug I used


calculation measures in cm

ball area r*3.14*r^2 =308,6544cm2

ball area divider 308.6544/4.956 =62,2789

side^2= a/62.2789= 4.956

then the segment side proitatto on the ball about 2.2cm instead in the sketch 2cm


Sorry for the rush in writing but I have to run away
 
but why if you change the size of the polygons the tipping changes? should not.. .
 
no no, it is a simple proportion between the circumference of the sphere and the side of the polygons.
I read somewhere that must be 68-70 cm.
 
but why if you change the size of the polygons the tipping changes? should not.. .
no tipping didn't change it was just to have the sides of the polygons at 20mm per side and I responded to max that he asked me the formula as I had made me the football ball... I calculated sphere and radius,

the quantity of taxes and always the same

Hi.

 

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