• This forum is the machine-generated translation of www.cad3d.it/forum1 - the Italian design community. Several terms are not translated correctly.

[inventor 2010] problem with design cam

  • Thread starter Thread starter LucaMF
  • Start date Start date

LucaMF

Guest
Good morning to all,

I turn to you because I can't in any way draw in 3d the piece of which you can find the attached 2d.
I tried more and more times with plans, 3d sketches and so on but nothing.
If any of you could help me, I would be infinitely grateful.
use inventor 2010 suite.

cordial greetings,
 

Attachments

Looking at the two figures above I can't see anything difficult, maybe it explains exactly what you can't do and where your inventor's knowledge comes.

It leaves me puzzled the figure below, maybe I'm ignorant about it, but I don't understand what the lower view is.
 
Looking at the two figures above I can't see anything difficult, maybe it explains exactly what you can't do and where your inventor's knowledge comes.

It leaves me puzzled the figure below, maybe I'm ignorant about it, but I don't understand what the lower view is.
I think it's the development of the throat on the cam. .
 
That's exactly what it is, and that's where my problems are born.
I tried with the sweep, using as a trajectory of the drawn curves with 3d sketch, the problem is that the throat does not have constant dimensions and I do not remain "parallele" to the cylindrical face
 
emboss/sbalzo command. . .
draw the sketch on a floor and then bounce it on the surface.. ;)
 
are there no problems with lengths?
on the table unfortunately I have the degrees, and not the lengths expressed in millimeters.. .
 
then, the bounce solution is correct, to make your profile, create a tangent plane to the cylinder where you will design the path.
your path presents the angular quotas developed, so you will have to do nothing but "develop" the projection corcoference, divide the circumference by 360 and then multiply by the number of degrees indicated in the quotas, for example for the first section that has a quota of 16°, the formula to write in the sketch of the first section will be 155*pi/360*16 (I in the file instead of writing 155 I took the quota of the diameter As the first sketch I made the line of half-carry at 15mm from the edge, now you will have to make an offset of the line of half-carry from both sides by half the thickness of the throat and finally join them to the final vertices to make it a closed region.
the only problem is that if you make the overhang of a geometry as long as the circumference, then the escalation from error, then I reduced one of the linear quotas of 0.001 (then in the formula will be for example 155*pi/360*16-0.001 for only one of the length quotas, obviously not those that quota the measurements at angle).
at this point you will make escalation processing giving necessary depth.
will remain a small wall that you will eliminate with the delete command face taking care to activate the "correggi" check.

Anyway, I'll send you back to the attached file.
 

Attachments

I thank you very much for the help, but I have a problem:
if you notice when the quarry leaves diagonally (from 15 to 45 on the lower side, to understand us) the sides do not remain parallel to the plane, so the mill would not be able to dig correctly... Is there any solution to this?
Thanks again
 
I imagined jumping out is what, I think there was a discussion about it a few years ago... and I think not in the inventor section.

It should be an optical effect of orthogonal projection, in fact it is precisely so, you see them "stored" because however it is as if you already see a piece of circumference before and after, but they are parallel, in fact if you put the work in plan and rough the view only around the central axis, you would see that when the faces pass from the center are parallel and even if you misuri the corner, they have no inclination.

It should be just as well in reality, in fact they should not be parallel to the plane, but passing through the center and are parallel to each other at the point where the visual proposition passes through the center.

I don't know if I explained, but if you think it's correct.
 
Look, if I didn't convince you look at this set, it is properly bound as if it were a frieze, it lacks only the transition bond that in years I haven't found the method of putting it, but if you try to move the cylinder in the throat (although while you move it, but in the eye you see it lost) in otrogonal view guradando the throat, you will see that the cylinder also follows the trend.
 

Attachments

... just lacks the transition bond that in years I have not yet found the method of putting it.. . .
when that bond can do it as the Buddhist commands, it will be too late.
Is there someone who can use it getting the desired result?
I have resigned but the fact that not even the Ilario has mastery consoles me:biggrin:

Bye.
 

Forum statistics

Threads
44,997
Messages
339,767
Members
4
Latest member
ibt

Members online

No members online now.
Back
Top