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stress analysis

  • Thread starter Thread starter Lorenzo_t80
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Lorenzo_t80

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Good evening, everyone. Some good Samaritan who gives me a few tips to use the environment solicitation analysis of inventor is there?
I simply need to understand how much an aluminum profile holds, which rests at the extremes 100 mm dx and 100 mm sx with a load above. I opened the environment and gave the material to the profile. I immediately got stuck with the constraints to put. I could not put a bond to the right and left of the particular; I flew so over by extrusion and selecting the extrusion face. I tried to put 100 n - 500 n - 5000 n but after making the simulation the piece seemed only to be very small. I set the real scale but it still leaves me doubts and perplexities. if someone can indicate me a guide or can explain me in small steps how to do it makes me a great pleasure. thanks to all and good eveningaaa
 

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without constraints the simulation will not be correct.
If I understand what you want to do, you could split the lower surface of the profile to the support distance, then on those surface sections apply the constraint.
 
Yes. I to overcome this problem I extruded 1 mm of material at the extremes of the profile to create a face on which to apply the constraints. The problem arises after me, how do I attack forces? It seems strange that 3 mt aluminum profile with 50 thousand kg above does not break. :eek:
 
the load you have to apply it to the surface, if distributed to the whole same, otherwise you have to divide it and apply the load to the desired portion.
is the material correctly defined? What results do you get?
 
the load you have to apply it to the surface, if distributed to the whole same, otherwise you have to divide it and apply the load to the desired portion.
is the material correctly defined? What results do you get?
How do I split it? Suppose we have a piece rested over 300 mm wide. to me put only one force in the center of the surface.

correct material. the results now place them
 

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create two floors at the desired distance and use the split command.
If I figured out how you proceeded, you're "saving" the load on the entire surface.
 
create two floors at the desired distance and use the split command.
If I figured out how you proceeded, you're "saving" the load on the entire surface.
Now I try to.. I hope I can
 

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It doesn't seem very high as a result, you have over 2000 mpa of stress.
the material that has resistance?
set the color bar to see the color distribution better.
where it will be red is the point with the greater stress.
 
It doesn't seem very high as a result, you have over 2000 mpa of stress.
the material that has resistance?
set the color bar to see the color distribution better.
where it will be red is the point with the greater stress.
what I care about should be von mises? Right? because I have seen that there are many solutions of solicitation, rightly. However the color scale is already active. That's why it doesn't fit. Shouldn't the color scale set it automatically?

material resistance: 10,08 wx/cm3 – 19,61 wy/cm3
 
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what I care about should be von mises? Right? because I have seen that there are many solutions of solicitation, rightly. However the color scale is already active. That's why it doesn't fit. Shouldn't the color scale set it automatically?

material resistance: 10,08 wx/cm3 – 19,61 wy/cm3
open the color bar setting, check "max value" or set the max value to a limit close to that of the material yielding or breaking load, depending on what you want to see.
also post the setting of the material.
 
open the color bar setting, check "max value" or set the max value to a limit close to that of the material yielding or breaking load, depending on what you want to see.
also post the setting of the material.
but the maximum value gives it to me according to the force I apply. The more I increase the more I give a high value.
 
no, the maximum value is the greater stress there is.
Of course, increased load increases stress.
set it, removing the flag to "maximum value", at a value close to the yield limit of the material and see what returns you.
 
How do I know the yield limit?
no, the maximum value is the greater stress there is.
Of course, increased load increases stress.
set it, removing the flag to "maximum value", at a value close to the yield limit of the material and see what returns you.
 
How do I know the yield limit?
If you don't know that or the broken load as you say the piece doesn't break?
those values you must have them in the material properties, find them in the technical sheet of the same.for that I asked if the material is correctly defined. . . .
 
If you don't know that or the broken load as you say the piece doesn't break?
those values you must have them in the material properties, find them in the technical sheet of the same.for that I asked if the material is correctly defined. . . .
material card purchased is this: technical characteristics
area
: 1079 mm2weight: 2,91 kg g/mlmoment di inerzia♪ 22,685 jx/cm4 ♪ 88,265 y/cm4resistance module: 10.08 wx/cm3 – 19.61 wycie/cm3lunghezza bar: 6040 mmmaterial: lega en aw 6060
 
material card purchased is this:technical characteristics
area
: 1079 mm2weight: 2,91 kg g/mlmoment di inerzia♪ 22,685 jx/cm4 ♪ 88,265 y/cm4resistance module: 10.08 wx/cm3 – 19.61 wycie/cm3lunghezza bar: 6040 mmmaterial: lega en aw 6060
is the inventor material defined with this data?
 
I would check that they were correct.
open the material editor and check it out.
However, with over 2000 mpa it breaks great.
 
@lorenzo_t80 you would explain to me that unit of measurement is: [Wx/cm3] never seen in my life... where did you get that data... the weight in my life? [kg/ml] (ml to my country are milliliters....)
I hope that before embarking on a fem you have the minimum basics of mechanics to understand what data to insert
 

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